我的主要活动中有一个列表视图和一个按钮,还有三个布局资源文件(right.xml,mid.xml和left.xml [它们是相对布局])。
我要创建一个arrayList(带有字符串和可绘制的(图像)),每次我按main.xml中的按钮时,arrayList的第一个内容将出现在屏幕的底部(左,中或右) ->取决于arrayList的顺序),当我再次单击时,下一项(字符串或可绘制对象)将出现在其下方,将其向上推动。
更新
我制作了一个模型和一个适配器
这是模特
public class ModelC1 {
public String C1Name;
public String C1Text;
public int id;
public boolean isSend;
public ModelC1(String C1Name, String C1Text, int id, boolean isSend){
this.id = id;
this.C1Name = C1Name;
this.C1Text = C1Text;
this.isSend = isSend;
}
public int getId(){
return id;
}
public void setId(int id){
this.id = id;
}
public String getC1Name() {
return C1Name;
}
public void setC1Name(String C1Name){
this.C1Name = C1Name;
}
public String getC1Text() {
return C1Text;
}
public void setC1Text (String C1Text){
this.C1Text = C1Text ;
}
public boolean isSend() {
return isSend;
}
public void setIsSend(boolean send){
isSend = send;
}
这是适配器
public class AdapterC1 extends BaseAdapter {
private List<ModelC1> listChat;
private LayoutInflater inflater;
private Context context;
public AdapterC1(List<ModelC1> listChat, Context context){
this.listChat = listChat;
this.context = context;
inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}
@Override
public int getCount() {
return listChat.size();
}
@Override
public Object getItem(int i) {
return listChat.get(i);
}
@Override
public long getItemId(int i) {
return i;
}
@Override
public View getView(int i, View convertView, ViewGroup viewGroup) {
View vi = convertView;
if(convertView == null ){
if(listChat.get(i).isSend() == 0)
vi=inflater.inflate(R.layout.list_send,null);
else if ((listChat.get(i).isSend() == 1))
vi=inflater.inflate(R.layout.list_recv,null);
else if ((listChat.get(i).isSend() == 2))
vi=inflater.inflate(R.layout.list_mid,null);
}else{
if(listChat.get(i).isSend() == 0)
vi=inflater.inflate(R.layout.list_send,null);
else if ((listChat.get(i).isSend() == 1))
vi=inflater.inflate(R.layout.list_recv,null);
else if ((listChat.get(i).isSend() == 2))
vi=inflater.inflate(R.layout.list_mid,null);
}
if(listChat.get(i).isSend() !=0 || listChat.get(i).isSend() !=1 || listChat.get(i).isSend() !=2 ){
BubbleTextView bubbleTextView = (BubbleTextView) vi.findViewById(R.id.bubbleChat);
if(bubbleTextView != null)
bubbleTextView.setText(listChat.get(i).C1Text);
TextView nameTextView = (TextView) vi.findViewById(R.id.nameChat);
if(nameTextView != null)
nameTextView.setText(listChat.get(i).C1Name);
}else{
vi=inflater.inflate(R.layout.list_mid,null);
BubbleTextView bubbleTextView = (BubbleTextView) vi.findViewById(R.id.bubbleChat);
bubbleTextView.setText("THE END");
}
return vi;
}
这是活动
公共类Chat1扩展了AppCompatActivity { 私有静态最终String TAG =“ Chat1”;
private AdapterC1 adapter;
private List<ModelC1> listChat = new ArrayList<>();
private int count = 1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_chat1);
RecyclerView chatContent1 = findViewById(R.id.chatContent1);
}
private ModelC1 setUpMessage(){
Log.d(TAG, "setUpMessage: Exec");
return();
}
///OnClick of the button in the activity_chat1.xml
public void nextClicked1(View view) {
Log.d(TAG, "nextClicked: Is Clicked");
///After the limit of the arraylist is reached
final int limit = 40;
if(count == limit){
Log.d(TAG, "nextClicked: Limit Reached");
Intent i = new Intent(Chat1.this, MainActivity.class);
startActivity(i);
}else{
///Call the list
loadList(null);
}
}
///Load the list of arrays?
public void loadList(View view){
ModelC1 chat = setUpMessage();
listChat.add(chat);
///The ID of the recycleview in the activity_chat1.xml
final RecyclerView recyclerview = findViewById(R.id.chatContent1);
///The adapter
final AdapterC1 adapter = new AdapterC1(listChat, this);
///Make the recyclerview always scroll
///the adapter
///recyclerview.setAdapter(adapter);
}
我现在的问题是如何创建ArrayList(包含字符串和可绘制对象)以及如何链接ArrayList以使其在单击按钮时一个接一个地显示?
对于ArrayList,这样的东西会起作用吗?
private List<List<String>> textChat1 = new ArrayList<List<String>>();
ArrayList<String> textChat1 = new ArrayList<String>();
textChat1.add("This is message 1");
textChat1.add("This is message 2");
textChat1.add("This is message 2");
addresses.add(textChat1);
如何添加图像以及如何说出哪些字符串使布局(左,中或右)膨胀?
答案 0 :(得分:1)
您可以这样操作:在您的Adapter
的{{1}}方法中,
getView
这可以完成您的工作,但是,我建议您使用@Override
public View getView(int position, View convertView, ViewGroup container) {
if (convertView == null) {
if (position == 1) {
convertView = getLayoutInflater().inflate(R.layout.left, container, false);
} else if (position == 2) {
convertView = getLayoutInflater().inflate(R.layout.mid, container, false);
} else {
convertView = getLayoutInflater().inflate(R.layout.right, container, false);
}
}
//your code here
return convertView;
}
,因为它在外观和内存管理方面更高效,更好。