我想用class="academicsList"
抓取ul中每个li的文本
要抓取的页面
https://www.eduvision.edu.pk/institutions-detail.php?city=51I&institute=3149_federal-urdu-university-of-arts-science-technology-islamabad
我遇到错误:navigateable string has no attribute text
请提出您是否有更好的逻辑
我是编程新手
这是我的代码
import requests
from bs4 import BeautifulSoup
from fake_useragent
import UserAgent
ua = UserAgent()
header = {'user-agent':ua.chrome}
response = requests.get('https://www.eduvision.edu.pk/institutions-detail.php?city=51I&institute=3149_federal-urdu-university-of-arts-science-technology-islamabad',headers=header)
soup = BeautifulSoup(response.content, 'html.parser')
disciplines = soup.findAll("ul", {"class": "academicsList"})
for d in disciplines:
for li in d:
print(li.text)
print("...............")
答案 0 :(得分:0)
欢迎您!
您正在尝试迭代找到的ul标签。但是您应该迭代li标签。为此,您需要在d中添加.findAll('li')
。喜欢,
for d in disciplines:
for li in d.findAll('li'):
print(li.text)
print("...............")
希望这会有所帮助!干杯!