This is my code我正在开发WPF应用程序,以在单击“更新”按钮时更新数据库。.我也想在单击“更新”按钮后将从数据库获取的数据重新加载到网格中...请帮我解决这个问题
答案 0 :(得分:1)
按钮单击事件代码
private void btnsave_Click(object sender, RoutedEventArgs e)
{
try
{
if (!IsPageValid())
{
}
else
{
feesGroup_Model.Name = txtname.Text;
feesGroup_Model.Description = txtdiscription.Text;
feesGroups_ViewModel.FeesGroup_Insert(feesGroup_Model);
lstvwCustomerslist.ItemsSource = feesGroups_ViewModel.BindFeesGroupData(txtSearch1.Text);
txtname.Text = string.Empty;
txtdiscription.Text = string.Empty;
lblmsg.Visibility = Visibility.Hidden;
errorgrid.Visibility = Visibility.Collapsed;
bindpaggination();
}
}
catch (Exception ex)
{
var abc = ex.ToString();
throw;
}
}
答案 1 :(得分:0)
:空模型:ObservableCollection list = new ObservableCollection();
private void bindpaggination()
{
var myList = GetData();
lstvwCustomerslist.ItemsSource = myList.Take(numberOfRecPerPage);
int count = myList.Take(numberOfRecPerPage).Count();
lblpageInformation.Content = count + " of " + myList.Count;
}
private ObservableCollection<FeeType_Model> GetData()
{
ObservableCollection<FeeType_Model> list = new ObservableCollection<FeeType_Model>();
var dt = feesType_ViewModel.BindALLFeesTypeData();
for (int i = 0; i < dt.Rows.Count; i++)
{
FeeType_Model feeType_Model = new FeeType_Model();
feeType_Model.Id = Convert.ToInt32(dt.Rows[i]["id"]);
feeType_Model.Type = dt.Rows[i]["type"].ToString();
feeType_Model.Code = dt.Rows[i]["code"].ToString();
feeType_Model.Is_active = dt.Rows[i]["is_active"].ToString();
feeType_Model.Created_at = dt.Rows[i]["created_at"].ToString();
feeType_Model.Description = dt.Rows[i]["description"].ToString();
list.Add(feeType_Model);
}
return list;
}
答案 2 :(得分:0)
我刚刚调用了在第一次加载窗口时用来调用动态按钮的方法,再次将其作为Button click事件。因此,通过从数据库中获取更新的列表来再次创建按钮。