Question

以下查询将生成10个更新的节点：

MATCH (a:ns3__Organization)-[r:ns4__isDomiciledIn]->(b:Resource)
WITH a,b LIMIT 10
SET a.isDomiciledIn = b.Country

我正在尝试通过以下查询将其应用到apoc.periodic.commit的整个图形中：

CALL apoc.periodic.commit("
MATCH (a:ns3__Organization)-[r:ns4__isDomiciledIn]->(b:Resource)
WITH a,b LIMIT $limit
SET a.isDomiciledIn = b.Country
", { limit : 50000});

以某种方式导致0更新。我在做什么错了？

感谢您的帮助。

Answer 1

您应该尝试以下一种方法：

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您出错：

否CALL apoc.periodic.commit(" MATCH (a:ns3__Organization)-[r:ns4__isDomiciledIn]->(b:Resource) WHERE NOT a.isDomiciledIn = b.Country WITH a,b LIMIT $limit SET a.isDomiciledIn = b.Country RETURN count(*) ", { limit : 50000});。这样您的查询永无止境
没有count(*)子句将结果过滤到仅尚未更新的节点

apoc.periodic.commit不会导致更新

1 个答案: