我不确定为什么我的找零值永远不会在第二个循环中求值,也不知道我的打印语句最终不会输出硬币。输入有效输入后,程序应将浮点数转换为int并输入下一个while循环。然后,根据更改值,应检查每个if语句中的条件是否为true,直到while条件为false为止。
#include <cs50.h>
#include <stdio.h>
int main(void) {
int coins = 0;
float n;
int change;
do
{
n = get_float("How much do I owe you? \n");
} while (n < 0); // continue prompt while true less than zero
change = n * 100;
while (change > 0)
{
if (change > 25) // change .25 cents
{
coins = coins + 1;
change = change - 25;
}
else if (change > 5 && change <= 10) // change 10 cents
{
coins = coins + 1;
change = change - 10;
}
else if (change > 1 && change <= 5) // change 5 cents
{
coins = coins + 1;
change = change - 5;
}
else // change 1 cents
{
coins = coins + 1;
change = change - 1;
}
return coins;
}
printf("%d\n", coins);
}
答案 0 :(得分:2)
问题来自return coins;
循环内的while
行。
您应该编写类似的内容:
while (change > 0)
{
/*update coins and change
but do not use return.*/
}
printf("%d\n", coins);
/* as return will exit from your function,
you want it at the end*/
return coins;