Flask-使用cURL获取带有json参数的请求

时间:2018-09-02 01:11:30

标签: python rest api curl flask

我已经使用python库flask开发了一个简单的REST API。这是我在做什么的示例:

from flask import Flask, request
import json

app = Flask(__name__)

@app.route("/")
def hello():
    json_arg = json.loads(request.args.get("json_arg", None))
    non_json_arg = request.args.get("non_json_arg", None)
    return "Hello, your json arg is: %s and your non_json_arg is %s"%(json_arg, non_json_arg)


if __name__ == '__main__':
    app.run(debug=True)

要测试我的代码,我已经以这种方式编写了python客户端:

import requests
import json

json_arg = [
            {
                "0": 1.3,
                "1": 1.4
            },
            {
                "0": 5.3,
                "1": 40.5
            }
        ]
non_json_arg = "some_arg"

arguments = {
    "json_arg": json.dumps(json_arg),
    "non_json_arg": non_json_arg
}

r = requests.get("http://localhost:5000", params=arguments, headers={"content-type": "application/json"})

print(r.text)

这很好用,输出为:

Hello, your json arg is: [{u'1': 1.4, u'0': 1.3}, {u'1': 40.5, u'0': 5.3}] and your non_json_arg is some_arg

出于测试的原因,我想对cURL做同样的事情,到目前为止,我测试的是:

curl -X GET --data '{"json_arg": [ { "0": 1.3, "1": 1.4 }, { "0": 5.3, "1": 40.5 } ], "non_json_arg":"some_arg"}' http://localhost:5000

但这会返回错误:

....
>> json_arg = json.loads(request.args.get("json_arg", None))
TypeError: expected string or buffer

我已经测试了cURL的许多其他参数,但是找不到这个简单问题的答案:

如何使用json参数将GET请求发送到API?

1 个答案:

答案 0 :(得分:0)

通常情况下,它会使用POST请求而不是get请求。看起来像这样:

curl -X POST -d '{"json_arg": [ { "0": 1.3, "1": 1.4 }, { "0": 5.3, "1": 40.5 } ], "non_json_arg":"some_arg"}' http://localhost:5000

但是,如果您确实想使用GET请求,则需要在实际的url中使用参数,这样它看起来就像:

curl -X GET http://localhost:5000/?json_arg=%5B%7B%220%22%3A+1.3%2C+%221%22%3A+1.4%7D%2C+%7B%220%22%3A+5.3%2C+%221%22%3A+40.5%7D%5D&non_json_arg=some_arg

我建议通常使用POST请求发送JSON数据。