这是我的用例: 我有两个来自两个可观察对象的对象数组,我创建了一个CombineLatest方法,以使用映射的ID将数组迭代为一个对象:
var result1 = [{
question: 1,
answerList: [{
answer: 'Sandra',
isDefault: 'true'
},
{
answer: 'John',
isDefault: 'false'
}
]
},
{
question: 2,
answerList: [{
answer: 'Peter',
isDefault: 'false'
},
{
answer: 'Bobby',
isDefault: 'false'
}
]
},
{
question: 3,
answerList: [{
answer: 'Harry',
isDefault: 'false'
},
{
answer: 'Bob',
isDefault: 'false'
}
]
}
]
var result2 = [{
question: 1,
answer: 'John'
},
{
question: 3,
answer: 'Bob'
}
];
我的目标是拥有另一个包含如下元素的对象数组:
var finalResult = [{
question: 1,
answerList: [{
answer: 'Sandra',
isDefault: 'false'
},
{
answer: 'John',
isDefault: 'true'
}
]
},
{
question: 2,
answerList: [{
answer: 'Peter',
isDefault: 'false'
},
{
answer: 'Bobby',
isDefault: 'false'
}
]
},
{
question: 3,
answerList: [{
answer: 'Harry',
isDefault: 'false'
},
{
answer: 'Bob',
isDefault: 'true'
}
]
}
]
答案 0 :(得分:1)
您可以使用哈希表来更快地检查设置了答案的问题。然后根据对象的设置迭代和更新项目。
var result1 = [{ question: 1, answerList: [{ answer: 'Sandra', isDefault: 'true' }, { answer: 'John', isDefault: 'false' }] }, { question: 2, answerList: [{ answer: 'Peter', isDefault: 'false' }, { answer: 'Bobby', isDefault: 'false' }] }, { question: 3, answerList: [{ answer: 'Harry', isDefault: 'false' }, { answer: 'Bob', isDefault: 'false' }] }],
result2 = [{ question: 1, answer: 'John' }, { question: 3, answer: 'Bob' }],
object = result2.reduce((o, { question, answer }) => {
(o[question] = o[question] || {})[answer] = true;
return o;
}, Object.create(null));
result1.forEach(({ question, answerList }) =>
answerList.forEach(o =>
o.isDefault = (question in object && o.answer in object[question]).toString()
)
);
console.log(result1);
.as-console-wrapper { max-height: 100% !important; top: 0; }
答案 1 :(得分:0)
示例代码:
let result = result1.map(item => {
let targetItems = result2.filter( item2 => item2.question ===
item.question );
targetItems.forEach(item3 => {
item.answerList.push(item3.answer);
});
return item;
});
console.log(result);