Question

我有此查询，需要基于branchId的每一行都缺少ActiveAgent。现在确定如何使其与branchId一起使用。当我在查询中有这样的查询时，它将为所有行返回1 amouth，但是当我尝试将其分开并像这样传递branchId时，它将起作用。

    …….
 ,(select Count(*)  from [TblAgencyContact] agent 
   left join [TblBranchMember] branchMember on agent.AgencyContactId = branchMember.AgencyContactId
                                                left join [TblBranch]branch  on branch.BranchId = branchMember.BranchId
                                               where agent.StatusId = 1 and branchMember.BranchId = branch.BranchId and 
                                               branchMember.BranchId = branch.BranchId) as ActiveAgents
,……

 from [TblBranch]branch

我不知道如何在查询中将当前行的BranchId传递给它。

select 
    Count(*)  
from 
    [TblAgencyContact] agent 
left join 
    [TblBranchMember] branchMember on agent.AgencyContactId = branchMember.AgencyContactId
left join 
    [TblBranch] branch on branch.BranchId = branchMember.BranchId
where 
    agent.StatusId = 1 
    and branchMember.BranchId = branch.BranchId 
    and branchMember.BranchId = branch.BranchId 
    and branch.BranchId = 81

Answer 1

您的顶部查询已关闭，但是您需要记住，您不需要在TblBranch表上进行JOIN，因为您正在将适当的值传递给子查询。另外，链接不应该是“内部联接”吗？如果TblBranchMember表中没有人，您就不想计算TblAgencyContact行，对吗？

(
    select Count(*)
    from [TblAgencyContact] agent 
    INNER join [TblBranchMember] branchMember 
        on agent.AgencyContactId = branchMember.AgencyContactId
    where agent.StatusId = 1 
        and branchMember.BranchId = branch.BranchId -- where branch is accessed in the outer query
) as ActiveAgents

需要将当前行的ID传递给SQL中的查询

1 个答案: