不幸的是,我无法控制API如何返回数据。我得到我得到的:/
我需要帮助来正确格式化我的数据,或者可能需要使用自定义管道正确显示数据。我尝试了不同的操作(mergeMap,过滤器,按管道分组等),但是我似乎无法完全得到想要的东西。任何帮助将不胜感激。
样本数据
[
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo1.jpg", "photoTitle": "Photo1"},
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo2.jpg", "photoTitle": "Photo2"},
{ "id": "rogersfr02", "first": "Fred", "last": "Rogers", "photo": "photo55.jpg", "photoTitle": "Photo55"},
...
]
组件
this.searchService.getData().subscribe(searchResults => {
this.searchResults = searchResults;
....? transform data here or custom pipe in template
});
所需结果(先显示名称,然后显示所有相关照片)
Bob Ross
Photo1
Photo2
Fred Rogers
Photo55
...
获得我想要的输出的最有效方法是什么?预先感谢!
答案 0 :(得分:1)
您可以使用loadash的groupBy
和toPairs
函数根据用户的名字和姓氏对数组数据进行分组,如下所示:-
var users = [
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo1.jpg", "photoTitle": "Photo1"},
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo2.jpg", "photoTitle": "Photo2"},
{ "id": "rogersfr02", "first": "Fred", "last": "Rogers", "photo": "photo55.jpg", "photoTitle": "Photo55"}
]
var result = _.groupBy(users, (user)=> user.first + ' ' + user.last);
result = _.toPairs(result);
console.log('Result: ', result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.js"></script>
您可以根据上述功能格式化或创建自己的自定义管道。
您可以参考以下stackblitz来查看有效的Angular解决方案。
答案 1 :(得分:1)
以下代码是我的纯RxJS解决方案:P
import { from } from 'rxjs';
import { groupBy, mergeMap, map, toArray, tap } from 'rxjs/operators';
let searchResults = [
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo1.jpg", "photoTitle": "Photo1"},
{ "id": "rossbo01", "first": "Bob", "last": "Ross", "photo": "photo2.jpg", "photoTitle": "Photo2"},
{ "id": "rogersfr02", "first": "Fred", "last": "Rogers", "photo": "photo55.jpg", "photoTitle": "Photo55"}
];
from(this.searchResults).pipe(
// Select necessary attributes
map(result => {
//console.log('Result:', result);
let fname = result['first'];
let lname = result['last'];
let photo = result['photoTitle'];
let rname = [fname, lname].join(' ');
return { rname, photo };
}),
// group objects by `rname` attribute
groupBy(result => result['rname']),
// return each item in group as array
mergeMap(group => {
//console.log('Group $1:', group);
return group.pipe(
toArray(),
);
}),
// Reduce arrays of objects
map(group => {
//console.log('Group $2:', JSON.stringify(group));
let rname = group[0]['rname'];
return group.reduce((a, b) => {
return {
rname: rname,
photo: [a.photo, b.photo],
};
});
}),
// Bypass and verify results
tap(result => console.log('Result:', result)),
).subscribe();