Question

我在桌子上有这样的东西

COUNTRY SCOPE1   SCOPE2 SCOPE3  SCOPE4  SCOPE5
UK          Y    NULL   NULL    NULL    NULL
UK      NULL          Y NULL    NULL    NULL
UK      NULL     NULL      Y    NULL    NULL

我需要将输出作为单行

COUNTRY SCOPE1  SCOPE2  SCOPE3  SCOPE4  SCOPE5
UK          Y        Y       Y  NULL    NULL

有人可以在MS SQL Server 2014中对此提供帮助吗？

Answer 1

您可以尝试使用MAX函数。

CREATE TABLE T(
    COUNTRY VARCHAR(50),
    SCOPE1 VARCHAR(3),
   SCOPE2 VARCHAR(3),
   SCOPE3 VARCHAR(3),
   SCOPE4 VARCHAR(3),
   SCOPE5 VARCHAR(3)
);


INSERT INTO T VALUES ('UK','Y',NULL,NULL,NULL,NULL);
INSERT INTO T VALUES ('UK',NULL,'Y',NULL,NULL,NULL);
INSERT INTO T VALUES ('UK',NULL,NULL,'Y',NULL,NULL);

查询1 ：

SELECT COUNTRY ,
        MAX(SCOPE1) AS SCOPE1,
        MAX(SCOPE2) AS SCOPE2,
        MAX(SCOPE3) AS SCOPE3,
        MAX(SCOPE4) AS SCOPE4,
        MAX(SCOPE5) AS SCOPE5
FROM T
GROUP BY COUNTRY

Results ：

| COUNTRY | SCOPE1 | SCOPE2 | SCOPE3 | SCOPE4 | SCOPE5 |
|---------|--------|--------|--------|--------|--------|
|      UK |      Y |      Y |      Y | (null) | (null) |

Answer 2

您可以使用聚合函数max或min都适用于您的数据集

SELECT COUNTRY ,
        MAX(SCOPE1) as  SCOPE1,
        MAX(SCOPE2) as  SCOPE2,
        MAX(SCOPE3) as  SCOPE3,
        MAX(SCOPE4) as  SCOPE4,
        MAX(SCOPE5) as  SCOPE5
FROM yourtable
GROUP BY COUNTRY

http://sqlfiddle.com/#!18/3960c/1

COUNTRY     SCOPE1  SCOPE2  SCOPE3  SCOPE4  SCOPE5
UK           Y        Y       Y     (null)  (null)

或

SELECT COUNTRY ,
        min(SCOPE1) as  SCOPE1,
        min(SCOPE2) as  SCOPE2,
        min(SCOPE3) as  SCOPE3,
        min(SCOPE4) as  SCOPE4,
        min(SCOPE5) as  SCOPE5
FROM yourtable
GROUP BY COUNTRY

http://sqlfiddle.com/#!18/3960c/2

COUNTRY     SCOPE1  SCOPE2  SCOPE3  SCOPE4  SCOPE5
UK            Y      Y         Y    (null)  (null)

将多行合并为一个

2 个答案: