Question

我正在尝试创建一个在输入“ ^”字符后大写字符串中下一个字符的函数。代码如下：

void decodeshift( string orig, string search, string replace )
{
    size_t pos = 0;

    while (true) {
    pos = orig.find(search, pos);
    if(pos == string::npos)
        break;
    orig.erase(pos, search.length());
    orig.replace(pos, search.length(), replace);

    cout<<orig<<endl;
    }
}

int main()
{
    string question = "What is the message? ";
    string answer = "The real message is ";

    string shift="^";
    string test="a";

    string answer1;

    //output decoded message
    string answer2;

    cout << question;
    cin >> answer1;
    cout << "decoding . . . " << "\n";

    //decodeback(answer1, back);
    decodeshift(answer1, shift, test);
    return 0;
}

我的输入将是：

^hello

所需的输出：

Hello

当前输出

aello

我似乎找不到要使用的正确函数，而我对在这种情况下如何使用toupper感到困惑。我只需要找到合适的替代品。

Answer 1

尝试更多类似的方法：

#include <cctype>

void decodeshift( string orig, string search )
{
    size_t pos = orig.find(search);
    while (pos != string::npos)
    {
        orig.erase(pos, search.length());
        if (pos == orig.size()) break;
        orig[pos] = (char) std::toupper( (int)orig[pos] );
        pos = orig.find(search, pos + 1);
    }
    return orig;
}

...

answer1 = decodeshift(answer1, "^");
cout << answer1 << endl;

或者，只需删除shift参数：

#include <cctype>

string decodeshift( string orig )
{
    size_t pos = orig.find('^');
    while (pos != string::npos)
    {
        orig.erase(pos, 1);
        if (pos == orig.size()) break;
        orig[pos] = (char) std::toupper( (int)orig[pos] );
        pos = orig.find('^', pos + 1);
    }
    return orig;
}

...

answer1 = decodeshift(answer1);
cout << answer1 << endl;

C ++：使用另一个字符将一个字符大写

1 个答案: