Question

我对这个fql.query方法有一些问题：

select music 
  from user 
  where uid = ...... 
    and music in (select music 
                    from user
                    where uid = ......
                 )

我想获得两个用户之间共同的音乐兴趣;它适用于像这样的查询

select uid 
  from user
  where uid = ......
    and uid in (select uid 
                  from user
                  where uid = ......
               )

我认为问题是第二个查询返回一个整数，第一个返回一个字符串数组。任何人都可以帮我这个吗？

（请原谅我糟糕的英语！我来自西班牙;））

Answer 1

第一个查询是否已经为您提供了答案？

我的意思是它执行以下操作：

-- Display only music field
select music 
from user 
where uid = <first_USER> -- Selection of your first user 
and music in ( -- We want to macth the string with another
    select music -- Selects only the music field
    from user
    where uid = <second_USER> -- Selection of your second user
)

因此，您获得了两个用户记录中匹配的音乐名称。

你的第二个问题对我来说有点奇怪：

select uid
  from user
  where uid = <first_USER?>
    and uid in (select uid 
                  from user
                  where uid = <second_USER?>
               )

其中基本上转换为找到user_id匹配用户1和用户2。事情永远不会发生，因为每个用户都拥有自己的uid。

顺便说一句，我不知道facebook如何处理音乐字符串，但似乎用户不会以常见的拼写和/或格式编写自己喜欢的音乐名称。这可能会妨碍您的匹配系统。

Answer 2

我试过了：

select music 
  from user 
  where uid=UID1
AND music IN (SELECT music from user where uid=UID2)

当UID1 music字符串与UID2的字符串完全匹配时，它可以正常工作。

Facebook fql.query的问题

2 个答案: