我正在实现多级数据表,而不使用任何插件或库。我想基于javaScript,JQuery或angular js实现。我检查了以下链接之一,
Traverse all the Nodes of a JSON Object Tree with JavaScript
但是我的json结构与上面的链接不同。
我需要在Tree Structure UI中显示我的JSON。我没有html的硬编码级别。所有级别均应使用javascript处理。
我已经实现了jsfiddle:http://jsfiddle.net/varunPes/0n9fmawb/40/
JSON结构
[ {
Home:{
"checkbox_view":true,
"checkbox_edit":false,
"checkbox_delete":true
}
},
{
"watchColorWorld":{
"local":{
"app-local-black":{
"checkbox_view":true,
"checkbox_edit":true,
"checkbox_delete":true
}
},
"global":{
"app-global-red":{
"checkbox_view":true,
"checkbox_edit":true,
"checkbox_delete":true
}
},
"world":{
"app-world-green":{
"checkbox_view":true,
"checkbox_edit":true,
"checkbox_delete":true
}
}
}
},
{
"systemMgmt":{
"checkbox_view":true,
"checkbox_edit":true,
"checkbox_delete":true
}
},
{
"rules":{
"Rule1":{
"rule2":{
"rule3":{
"checkbox_view":true,
"checkbox_edit":true,
"checkbox_delete":true
}
}
}
}
}
]
您的回答对我很有价值。预先感谢。
答案 0 :(得分:0)
我想用香草Javascript实现的最简单的方法是修改对象的深度优先遍历:
function renderJSON(json) {
const wrapper = document.createElement('div');
const stack = [{
node: json,
name: 'root',
parentEl: wrapper
}];
while (stack.length > 0) {
let current = stack.pop();
let currentObj = current.node;
let currentParentEl = current.parentEl;
let level = document.createElement('div');
level.classList.add('level');
level.textContent = current.name + ': ';
if (currentObj.renderContent) {
// render custom html content
currentObj.renderContent(level);
} else if (!(currentObj instanceof Object)) {
level.textContent += currentObj;
}
currentParentEl.append(level);
if (currentObj instanceof Object) {
let keys = Object.keys(currentObj);
if (!currentObj.skipChildren) {
// push in reverse to preserve key order
for (let i = keys.length - 1; i >= 0; i--) {
let key = keys[i];
let node = currentObj[key];
stack.push({
node: node,
name: key,
parentEl: level
});
}
}
}
}
return wrapper;
}
// Example Use Case:
const Permissions = function Permissions() {
this.skipChildren = true;
this.view = false;
this.edit = false;
this.delete = false;
};
Permissions.prototype = {
renderContent(el) {
const fields = ['view', 'edit', 'delete'];
for (let field of fields) {
const label = document.createElement('label');
label.textContent = field;
const checkbox = document.createElement('input');
checkbox.type = 'checkbox';
checkbox.checked = this[field];
label.appendChild(checkbox);
el.appendChild(label);
}
}
};
const rendered = renderJSON({
element1: {
a: 4,
b: 6,
c: 24,
element1a: {
a: 'hello'
}
},
element2: {
a: 'abc',
permissions: new Permissions()
},
element3: ["first", "second", "third"]
});
document.body.append(rendered);
.level {
margin-left: 1em;
}
根据您的需要,可以使用很多不同的方法来分支此代码。由于您已获得一个JSON字符串开头,因此您需要找到某种方法将其转换为可产生所需结果的Javascript对象。