我有以下用于接收消息的代码:
private void DataMessage(NetIncomingMessage msg)
{
NetOutgoingMessage outmsg = server.CreateMessage();
DataType data = (DataType)msg.ReadByte();
switch (data)
{
case DataType.DATATYPEMSG:
string s = msg.ReadString();
Console.WriteLine(s);
outmsg.Write(s);
outmsg.Write((byte)DataType.DATATYPEMSG);
server.SendToAll(outmsg,NetDeliveryMethod.ReliableUnordered);
break;
case DataType.DATATYPEOTHER:
outmsg.Write((byte)DataType.DATATYPEMSG);
outmsg.Write("please try this again later");
server.SendMessage(outmsg,msg.SenderConnection,NetDeliveryMethod.ReliableUnordered);
break;
case DataType.DATATYPEREQUEST:
break;
default: msg.SenderConnection.Disconnect("if you believe you where wrongly picked up for editing the code please contact the developer");
break;
}
}
以及发送这些代码的代码:
internal void sendmsg(string v)
{
NetOutgoingMessage outmsg = tclient.CreateMessage(v);
outmsg.Write((byte)DataType.DATATYPEMSG);
tclient.SendMessage(outmsg, NetDeliveryMethod.ReliableUnordered);
}
,如果消息到达服务器,则仅调用默认值并断开与用户的连接。
答案 0 :(得分:0)
创建消息时,您将消息文本写在DataType之前,但是收到消息时,您希望DataType出现在文本之前。
您可以通过在文本之前编写DataType来解决此问题,如下所示:
internal void sendmsg(string v)
{
NetOutgoingMessage outmsg = tclient.CreateMessage();
outmsg.Write((byte)DataType.DATATYPEMSG);
outmsg.Write(v);
tclient.SendMessage(outmsg, NetDeliveryMethod.ReliableUnordered);
}
答案 1 :(得分:0)
我改变了
NetOutgoingMessage outmsg = server.CreateMessage();
DataType data = (DataType)msg.ReadByte();
switch (data)
{
case DataType.DATATYPEMSG:
string s = msg.ReadString();
至:
NetOutgoingMessage outmsg = server.CreateMessage();
DataType data = (DataType)msg.ReadByte();
string s = msg.ReadString();