我有一个闪亮的应用程序,其中有两个表。如您所见,用户使用右边的数据表和那里的小部件,以便在左边的rhandsontable中显示结果。该应用程序可以按预期运行,除了每次我通过selectInput()
“标签”选择一个不同的测试的事实都会丢失之前所做的所有更改之前,并且左侧的rhandsontable会“重新启动”。我使用this来保留修改后的名称,但是我需要对整个应用程序应用类似的逻辑。
应用的逻辑:
用户通过使用selectInput()“ Label”选择测试之一。这是主要操作,然后他可以修改其名称,例如将Test 1更改为TestA。然后,用户可以通过numericInput()“ Tests中的项目”在Test中添加项目。这些是总项目。正如您将看到的,“测试中的项目”的数目与hot3表中“测试”中“可用”列的数目相同。通过“选择项目”,他可以选择要在hot5表中显示的特定项目。然后,用户可以单击hot5表以选择特定项目,并且针对该特定测试,hot3表中“ Sel”列下的选定项目(或行)数将显示。 “选择的项目”仅显示在“选择项目”中选择的项目数。请注意,对该表进行的每次修改都不依赖于其他小部件。例如,这意味着不必更改标签名称。
library(shiny)
library(DT)
library(rhandsontable)
library(tidyverse)
ui <- navbarPage(
"Application",
tabPanel("Booklets",
sidebarLayout(
sidebarPanel(
uiOutput("tex2"),
rHandsontableOutput("hot3")
),
mainPanel(
fluidRow(
wellPanel(
fluidRow(
column(4,
DT::dataTableOutput("hot5")
),
column(4,
fluidRow(
uiOutput("book3"),
uiOutput("book6")
),
fluidRow(
uiOutput("book1"),
uiOutput("book10"),
uiOutput("book11")
)
)
))
)
)
)
)
)
#server
server <- function(input, output, session) {
output$tex2<-renderUI({
numericInput("text2", "#tests", value = 1, min=1)
})
output$book1<-renderUI({
numericInput("bk1",
"Items in test",
value = 1,
min = 1)
})
output$book3<-renderUI({
selectInput("bk3",
"Label",
choices=(paste("Test",1:input$text2)))
})
output$book6<-renderUI({
textInput("bk6", "Change to",
value=NULL
)
})
output$book10<-renderUI({
selectizeInput(
"bk10", "Select Items", choices =1:10000,multiple =T,selected = 1,
options = list(maxItems = input$bk1))
})
output$book11<-renderUI({
textInput("bk11", "Items chosen",
value = nrow(rt5())
)
})
rt4<-reactive({
if(is.null(input$bk6)|input$bk6==""){
if(is.null(input$hot5_rows_selected)|| is.na(input$hot5_rows_selected)){
DF=data.frame(
Sel. = rep(TRUE, input$text2),
Test=paste(1:input$text2),
Label=paste("Test",1:input$text2),
Avail.=format(round(as.integer(rep.int(input$bk1,input$text2))),0),
Sel =as.integer(rep.int(0,input$text2)),
stringsAsFactors = FALSE)
}
else{
DF=data.frame(
Sel. = rep(TRUE, input$text2),
Test=paste(1:input$text2),
Label=paste("Test",1:input$text2),
Avail.=format(round(as.integer(rep.int(input$bk1,input$text2))),0),
Sel =as.integer(rep.int(0,input$text2)),
stringsAsFactors = FALSE)
}
for(i in 1 : input$text2){
if(DF[i,3]==input$bk3){
DF[i,4]<-input$bk1
DF[i,5]<-length(input$hot5_rows_selected)
}
else{
DF[i,4]<-1
}
}
DF
}
else{
if(is.null(input$hot5_rows_selected)|| is.na(input$hot5_rows_selected)){
DF=data.frame(
Sel. = rep(TRUE, input$text2),
Test=paste(1:input$text2),
Label=paste("Test",1:input$text2),
Avail.=format(round(as.integer(rep.int(input$bk1,input$text2))),0),
Sel =as.integer(rep.int(0,input$text2)),
stringsAsFactors = FALSE)
DF[DF==input$bk3]<-input$bk6
DF
}
else{
DF=data.frame(
Sel. = rep(TRUE, input$text2),
Test=paste(1:input$text2),
Label=paste("Test",1:input$text2),
Avail.=format(round(as.integer(rep.int(input$bk1,input$text2))),0),
Sel =as.integer(rep.int(0,input$text2)),
stringsAsFactors = FALSE)
DF[DF==input$bk3]<-input$bk6
DF
}
for(i in 1 : input$text2){
if(DF[i,3]==input$bk6){
DF[i,4]<-input$bk1
DF[i,5]<-length(input$hot5_rows_selected)
}
else{
DF[i,4]<-1
}
}
DF
}
})
rt55<-reactive({
DF=data.frame(
Id= input$bk10,
Label=paste("Item",input$bk10),
Pf=0,
stringsAsFactors = FALSE
)
})
rt5<-reactive({
DF=data.frame(
Id= input$bk10,
Label=paste("Item",input$bk10),
Pf=0,
stringsAsFactors = FALSE
)
cbind(id=rowSelected(), DF)
})
rowSelected <- reactive({
x <- numeric(nrow(rt55()))
x[input$hot5_rows_selected] <- 1
x
})
output$hot5 <- renderDT(datatable(rt5()[,-1],
selection = list(mode = "multiple",
selected = (1:nrow(rt5()[,-1]))[as.logical(rowSelected())],
target = "row"),rownames = F)
)
output$hot3 <-renderRHandsontable(
rhandsontable(rt4())
)
}
答案 0 :(得分:1)
根据评论进行编辑。我认为代码可以工作,但它相当脆弱,需要相当程度的错误处理。例如,点击提交后重置条目
private ICommand _AddItemCmd;
public ICommand AddItemCmd
{
get
{
if (_AddItemCmd == null)
_AddItemCmd = new CreateCommand(AddItemToList,IsProductItemEmpty);
return _AddItemCmd;
}
set
{
_AddItemCmd = value;
}
}
public void AddItemToList(){
//My blah blah code
}
public bool IsProductItemEmpty(){
//return true
//OR
//return false
}