Question

我有以下数组：

$booking_array = array(

    "2018-09-01"=>array("360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

echo '<pre>',print_r($booking_array),'</pre>';

我只希望在整个数组中获得最多的特定值出现次数。

例如，“ 360”的最高出现次数是“ 3”，而“ 520”的最高出现次数是“ 2”。

我正在像这样使用array_count_values：

foreach($booking_array as $key => $val) {

    print_r(array_count_values($val));

}

哪个输出：

Array
(
    [360] => 3
)

Array
(
    [360] => 2
)

Array
(
    [360] => 1
    [520] => 1
)

Array
(
    [360] => 2
)

Array
(
    [360] => 1
    [520] => 2
)

但是我不明白如何只采用最高值并将其转换为：

Array
(
    [0] => 360
    [1] => 360
    [2] => 360
    [3] => 520
    [4] => 520
)

感谢任何帮助。

Answer 1

我认为这是找到所需值的最简单方法。

这使用array_count_values并对降序排列的数组进行排序，并获取第一个项目键。

foreach($booking_array as $booking) {
    $array_count=array_count_values($booking);
    arsort($array_count); // sort it descending
    $result[] = key($array_count);  // get first items key
}

var_dump($result);

https://3v4l.org/WrkRf

Answer 2

首先，我们创建一个小函数使事情变得更容易：

 function mergeIfGreaterThan($x,$y){
    /*
        this function merge two arrays .Each existing value of $x is 
        replaced by its corresponding in $y if it is greater than it.If a value doesn't
        exist in $x  but exists in $y it is automatically added to $x
    */
    if(!is_array($x)||!is_array($y)) return false;
    foreach($x as $k=>$v){
        if(isset($y[$k])){
            if($y[$k]>$v)
                $x[$k]=$y[$k];
            unset($y[$k]);
        }

    }
    if(!empty($y))
    foreach($y as $k=>$v){
        $x[$k]=$v;
    }
    return $x;
}

给出此数组：

$booking_array = array(

    "2018-09-01"=>array("360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

我们这样处理：

$x=array();//create an empty array
foreach($booking_array as $value){//grab the max number of occurences of each value 
    $x=mergeifgreaterthan($x,array_count_values($value)); 
}
$result=array();//create another empty array to contain the result
foreach($x as $k=>$v){//loop through the array of number of occurences
    for($i=$v;$i>0;$i--){//append the value to the result array the number of times each value occurs
        $result[]=$k;
    }
}
print_r($result);

输出：

Array
(
    [0] => 360
    [1] => 360
    [2] => 360
    [3] => 520
    [4] => 520
)

Answer 3

遵循此步骤

第1步：创建一个多维数组以存储值并存在最高的在线状态

第2步：进行Forloop或Foreach遍历数组

第3步：从数组中找到最大值并更新多维数组

第4步：根据需要使用多维数组进行打印

如果您有5个存在的320和3个存在的540，那么

    $a=array();
    for($i=0;$i>arraycount;$i++)
       {
          array_push($a,"value");
       }

    print_r($a);

Answer 4

$booking_array = array(

    "2018-09-01"=>array("520","360","360","360"),
    "2018-09-02"=>array("360","360"),
    "2018-09-03"=>array("360","520"),
    "2018-09-04"=>array("360","360"),
    "2018-09-05"=>array("360","520","520"),

);

echo '<pre>',print_r($booking_array),'</pre>';

foreach($booking_array as $booking) {
    $array_count=array_count_values($booking);
    $value = max($array_count);
    $key = array_search($value, $array_count);
    echo $key.'--'.$value.'times'.'<br/>';

}

尝试一下

PHP数组计算值的唯一出现次数

4 个答案: