Question

大家好，我来找您是因为我的ajax脚本有一个小问题，我分享了我的代码，并告诉我是否存在问题，感谢您的进步，如果您有任何解决方案，我感谢您，这是一个错误：

Argument 1 passed to App \ Repository \ ProductRepository :: findBySearch () must be of the string type, object given, called in C: \ wamp64 \ www \ Shop \ src \ Controller \ FrontController.php on line 201

我的控制器：

/**
     * @Route("/recherche/", name="search", methods="POST")
     * @param Request $request
     * @return Response
     */
    public function search(Request $request): Response{

        $search = $this->createForm(SearchType::class);
        $search->handleRequest($request);

        if($request->isXmlHttpRequest()) {

           $value = $search['name'];
           $result = $this->getDoctrine()->getRepository(Product::class)->findBySearch($value);

           return new JsonResponse($result);
        }

        return $this->render('inc/search.html.twig', [
            'title' => 'Effectuer une recherche',
            'search' => $search->createView()
        ]);

    }

我的执行SQL查询的存储库：

/**
     * @param $value
     * @return string
     * @throws \Exception
     */
    public function findBySearch(string $value) {

        $bool = 1;
        $query = $this->createQueryBuilder('r')
            ->select('r')
            ->orwhere('r.name LIKE :chaine')
            ->orWhere('r.description LIKE :chaine')
            ->andWhere('r.isPublished = :bool')
            ->orderBy('r.createdAt', 'DESC')
            ->setParameter(':chaine', '%'.$value.'%')
            ->setParameter(':bool', $bool)
            ->getQuery();

        try {
            return $query->getResult();
        }
        catch (\Exception $e) {
            throw new \Exception('Problème' . $e->getMessage());
        }
    }

这是我的代码，允许我提出Ajax请求

<!-- Modal Search -->
<div class="modal-search-header flex-c-m trans-04 js-hide-modal-search">
    <div class="container-search-header">
        <button class="flex-c-m btn-hide-modal-search trans-04 js-hide-modal-search">
            <img src="images/icons/icon-close2.png" alt="CLOSE">
        </button>
        <div id="resultat"></div>
         {{ form_start(search, {'method': 'POST', 'attr': {'class': 'wrap-search-header flex-w p-l-15', 'id': 'form'}}) }}
            <button class="flex-c-m trans-04">
                <i class="zmdi zmdi-search"></i>
            </button>
            {{ form_widget(search.name) }}

        {{ form_end(search) }}
    </div>
</div>

<script>

    $(document).ready(function(){

        $("#form").keypress(function(){

            $.ajax({
                type:"POST",
                data: $(this).serialize(),
                url:"{{ path('search') }}",
                success: function(data){
                    $("#search_name").html(data);
                    $.post( "{{ path('search') }}", function( data ) {
                        $( "#resultat" ).html( data );
                    });
                },
                error: function(){
                    $("#search_name").html('Une erreur est survenue.');
                }
            });
            return false;
        });
    });
</script>

Answer 1

替换

$value = $search['name'];

与

$value = $search->get('name')->getNormData();

由于$search是FormInterface对象，因此仅通过$search['name']就不会获得提交的值。您可以调用$search->getData()来获取整个表单数据，或者调用$search->get('YOUR_FIELD_NAME')->getNormData()来获取特定值

另外，考虑用

包装

if($search->isSubmitted()) {

   if($request->isXmlHttpRequest()) {
     // ... 
   }
}

Symfony Ajax请求错误500

1 个答案: