我正在制作一个Spring Boot REST应用程序。我正在尝试制作一个多部分表单上载控制器,它将一起处理表单数据和文件上载。这是我目前的控制器代码:
@RequestMapping(value = "", method = RequestMethod.POST, headers="Content-Type=multipart/form-data")
@PreAuthorize("hasRole('ROLE_MODERATOR')")
@ResponseStatus(HttpStatus.CREATED)
public void createNewObjectWithImage(
/*@RequestParam(value="file", required=true) MultipartFile file,
@RequestParam(value="param_name_1", required=true) final String param_name_1,
@RequestParam(value="param_name_2", required=true) final String param_name_2,
@RequestParam(value="param_name_3", required=true) final String param_name_3,
@RequestParam(value="param_name_4", required=true) final String param_name_4,
@RequestParam(value="param_name_5", required=true) final String param_name_5*/
@ModelAttribute ModelDTO model,
BindingResult result) throws MyRestPreconditionsException {
//ModelDTO model = new ModelDTO(param_name_1, param_name_2, param_name_3, param_name_4, param_name_5);
modelValidator.validate(model, result);
if(result.hasErrors()){
MyRestPreconditionsException ex = new MyRestPreconditionsException(
"Model creation error",
"Some of the elements in the request are missing or invalid");
ex.getErrors().addAll(
result.getFieldErrors().stream().map(f -> f.getField()+" - "+f.getDefaultMessage()).collect(Collectors.toList()));
throw ex;
}
// at the moment, model has a MultipartFile property
//model.setImage(file);
modelServiceImpl.addNew(model);
}
我尝试使用@ModelAttribute批注和发送请求参数,但是这两种方法都失败了。
这是我发送的请求:
---------------------------acebdf13572468
Content-Disposition: form-data; name="file"; filename="mint.jpg"
Content-Type: image/jpeg
<@INCLUDE *C:\Users\Lazaruss\Desktop\mint.jpg*@>
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_1”
string_value_1
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_2”
string_value_2
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_3”
string_value_3
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_4”
string_value_4
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_5”
string_value_5
---------------------------acebdf13572468--
我的应用程序是无状态的,并与授权机构一起使用spring安全性。 在我的安全包中,我包含了AbstractSecurityWebApplicationInitializer类
public class SecurityApplicationInitializer extends AbstractSecurityWebApplicationInitializer {
@Override
protected void beforeSpringSecurityFilterChain(ServletContext servletContext) {
insertFilters(servletContext, new MultipartFilter());
}
}
我还在@Configuration类中使用StandardServletMultipartResolver
然后在我的WebInitializer中,添加以下代码:
MultipartConfigElement multipartConfigElement = new MultipartConfigElement("/tmp",
3 * 1024 * 1024, 6 * 1024 * 1024, 1 * 512 * 1024);
apiSR.setMultipartConfig(multipartConfigElement);
当我尝试将控制器与注释的代码(@RequestParams批注)一起使用时,出现404未找到错误。 当我尝试使用带有@ModuleAttribute批注的控制器时,模型对象为空。
答案 0 :(得分:7)
我有类似的问题。当您要发送对象+多部分时。您必须(或者至少我不知道其他解决方案)使您的控制器像这样:
public void createNewObjectWithImage(@RequestParam("model") String model, @ReqauestParam(value = "file", required = false) MultipartFile file)
然后:使用以下命令将字符串转换为对象:
ObjectMapper mapper = new ObjectMapper();
ModelDTO modelDTO = mapper.readValue(model, ModelDTO.class);
答案 1 :(得分:0)
可以接收对象和文件
@PostMapping(value = "/v1/catalog/create", consumes = MediaType.MULTIPART_FORM_DATA_VALUE )
public void createNewObjectWithImage(
@RequestPart ModelTO modelTO,
@RequestPart MultipartFile image)
ModelTO
public class ModelTO {
private String name;
public ModelTO() {
super();
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
和curl示例:
curl -X POST "https://your-url.com/v1/catalog/create" -H "accept: application/json;charset=UTF-8" -H "Content-Type: multipart/form-data" -F "image=@/pathtoimage/powerRager.jpg;type=image/jpeg" -F "modelTO={\"name\":\"White\"};type=application/json;charset=utf-8"
Postman和其他软件不支持发送应用程序/ json类型的表单数据参数。