Spring Boot上传表单数据和文件

时间:2018-08-20 20:26:47

标签: java spring-boot spring-security multipartform-data

我正在制作一个Spring Boot REST应用程序。我正在尝试制作一个多部分表单上载控制器,它将一起处理表单数据和文件上载。这是我目前的控制器代码:

    @RequestMapping(value = "", method = RequestMethod.POST, headers="Content-Type=multipart/form-data")
    @PreAuthorize("hasRole('ROLE_MODERATOR')")
    @ResponseStatus(HttpStatus.CREATED)
    public void createNewObjectWithImage(
            /*@RequestParam(value="file", required=true) MultipartFile file,
            @RequestParam(value="param_name_1", required=true) final String param_name_1,
            @RequestParam(value="param_name_2", required=true) final String param_name_2,
            @RequestParam(value="param_name_3", required=true) final String param_name_3,
            @RequestParam(value="param_name_4", required=true) final String param_name_4,
            @RequestParam(value="param_name_5", required=true) final String param_name_5*/
            @ModelAttribute ModelDTO model,
            BindingResult result) throws MyRestPreconditionsException {

        //ModelDTO model = new ModelDTO(param_name_1, param_name_2, param_name_3, param_name_4, param_name_5);

        modelValidator.validate(model, result);
        if(result.hasErrors()){
            MyRestPreconditionsException ex = new MyRestPreconditionsException(
                    "Model creation error",
                    "Some of the elements in the request are missing or invalid");
            ex.getErrors().addAll(
                    result.getFieldErrors().stream().map(f -> f.getField()+" - "+f.getDefaultMessage()).collect(Collectors.toList()));
            throw ex;
        }
// at the moment, model has a MultipartFile property
        //model.setImage(file);
        modelServiceImpl.addNew(model);
    }

我尝试使用@ModelAttribute批注和发送请求参数,但是这两种方法都失败了。

这是我发送的请求:

---------------------------acebdf13572468
Content-Disposition: form-data; name="file"; filename="mint.jpg"
Content-Type: image/jpeg

<@INCLUDE *C:\Users\Lazaruss\Desktop\mint.jpg*@>
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_1”

string_value_1
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_2”

string_value_2
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_3”

string_value_3
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_4”

string_value_4
---------------------------acebdf13572468
Content-Disposition: form-data; name=”param_name_5”

string_value_5
---------------------------acebdf13572468--

我的应用程序是无状态的,并与授权机构一起使用spring安全性。 在我的安全包中,我包含了AbstractSecurityWebApplicationInitializer类

public class SecurityApplicationInitializer extends AbstractSecurityWebApplicationInitializer {

    @Override
    protected void beforeSpringSecurityFilterChain(ServletContext servletContext) {
            insertFilters(servletContext, new MultipartFilter());
        }
    }

我还在@Configuration类中使用StandardServletMultipartResolver

然后在我的WebInitializer中,添加以下代码:

MultipartConfigElement multipartConfigElement = new MultipartConfigElement("/tmp", 
                3 * 1024 * 1024, 6 * 1024 * 1024, 1 * 512 * 1024);        
apiSR.setMultipartConfig(multipartConfigElement);

当我尝试将控制器与注释的代码(@RequestParams批注)一起使用时,出现404未找到错误。 当我尝试使用带有@ModuleAttribute批注的控制器时,模型对象为空。

2 个答案:

答案 0 :(得分:7)

我有类似的问题。当您要发送对象+多部分时。您必须(或者至少我不知道其他解决方案)使您的控制器像这样:

public void createNewObjectWithImage(@RequestParam("model") String model, @ReqauestParam(value = "file", required = false) MultipartFile file)

然后:使用以下命令将字符串转换为对象:

ObjectMapper mapper = new ObjectMapper();
ModelDTO modelDTO = mapper.readValue(model, ModelDTO.class);

在Postman中,您可以这样发送: enter image description here

答案 1 :(得分:0)

可以接收对象和文件

@PostMapping(value = "/v1/catalog/create", consumes = MediaType.MULTIPART_FORM_DATA_VALUE )
public void createNewObjectWithImage(
         @RequestPart ModelTO modelTO,
         @RequestPart MultipartFile image)

ModelTO

public class ModelTO {

    private String name;


    public ModelTO() {
        super();
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

和curl示例:

curl -X POST "https://your-url.com/v1/catalog/create" -H  "accept: application/json;charset=UTF-8" -H  "Content-Type: multipart/form-data" -F "image=@/pathtoimage/powerRager.jpg;type=image/jpeg" -F "modelTO={\"name\":\"White\"};type=application/json;charset=utf-8"

Postman和其他软件不支持发送应用程序/ json类型的表单数据参数。