我知道我可以使用
获取表格列表SELECT TABLE_NAME FROM information_schema.tables
WHERE NOT TABLE_NAME='sysdiagrams'
AND TABLE_SCHEMA = 'dbo'
AND TABLE_TYPE= 'BASE TABLE'
但我不知道如何修改它以获得具有表的当前行数的第二列。我虽然喜欢这样的东西:
DECLARE @tbl VARCHAR(200)
(SELECT @tbl = TABLE_NAME, TABLE_NAME,
(SELECT COUNT(ID) AS Cnt FROM @tbl)
FROM information_schema.tables
WHERE NOT TABLE_NAME='sysdiagrams'
AND TABLE_SCHEMA = 'dbo'
AND TABLE_TYPE= 'BASE TABLE')
我知道上面的内容不是有效的T-SQL,但我认为它已经完成了喜欢所做的事情。这适用于SQL Server 2000.如果可能的话,我宁愿不使用存储过程。
答案 0 :(得分:13)
快速而肮脏的方式(包括未提交的更改以及可能在堆上的转发指针)
select o.name, rows
from sysindexes i join sysobjects o on o.id=i.id
where indid < 2 and type='U'
答案 1 :(得分:0)
exec sp_MSforeachtable 'select count(*) as nr_of_rows, ''?'' as table_name from ?'
答案 2 :(得分:0)
你可以全力以赴。使用sysIndexes获取行计数的问题在于它们并不总是最新的。但是,有一种方法可以使它们都是最新的。以下代码将为您提供每个表的行数以及更多的行数。
/**********************************************************************************************************************
Purpose:
Returns a single result set similar to sp_Space used for all user tables at once.
Notes:
1. May be used as a view, stored procedure, or table-valued function.
2. Must comment out 1 "Schema" in the SELECT list below prior to use. See the adjacent comments for more info.
Revision History:
Rev 00 - 22 Jan 2007 - Jeff Moden
- Initital creation for SQL Server 2000
Rev 01 - 11 Mar 2007 - Jeff Moden
- Add automatic page size determination for future compliance
Rev 02 - 05 Jan 2008 - Jeff Moden
- Change "Owner" to "Schema" in output. Add optional code per Note 2 to find correct schema name
**********************************************************************************************************************/
--===== Ensure that all row counts, etc is up to snuff
-- Obviously, this will not work in a view or UDF and should be removed if in a view or UDF. External code should
-- execute the command below prior to retrieving from the view or UDF.
DBCC UPDATEUSAGE(0) WITH COUNT_ROWS, NO_INFOMSGS
--===== Return the single result set similar to what sp_SpaceUsed returns for a table, but more
SELECT DBName = DB_NAME(),
--SchemaName = SCHEMA_NAME(so.UID), --Comment out if for SQL Server 2000
SchemaName = USER_NAME(so.UID), --Comment out if for SQL Server 2005
TableName = so.Name,
TableID = so.ID,
MinRowSize = MIN(si.MinLen),
MaxRowSize = MAX(si.XMaxLen),
ReservedKB = SUM(CASE WHEN si.IndID IN (0,1,255) THEN si.Reserved ELSE 0 END) * pkb.PageKB,
DataKB = SUM(CASE WHEN si.IndID IN (0,1 ) THEN si.DPages ELSE 0 END) * pkb.PageKB
+ SUM(CASE WHEN si.IndID IN ( 255) THEN ISNULL(si.Used,0) ELSE 0 END) * pkb.PageKB,
IndexKB = SUM(CASE WHEN si.IndID IN (0,1,255) THEN si.Used ELSE 0 END) * pkb.PageKB
- SUM(CASE WHEN si.IndID IN (0,1 ) THEN si.DPages ELSE 0 END) * pkb.PageKB
- SUM(CASE WHEN si.IndID IN ( 255) THEN ISNULL(si.Used,0) ELSE 0 END) * pkb.PageKB,
UnusedKB = SUM(CASE WHEN si.IndID IN (0,1,255) THEN si.Reserved ELSE 0 END) * pkb.PageKB
- SUM(CASE WHEN si.IndID IN (0,1,255) THEN si.Used ELSE 0 END) * pkb.PageKB,
Rows = SUM(CASE WHEN si.IndID IN (0,1 ) THEN si.Rows ELSE 0 END),
RowModCtr = MIN(si.RowModCtr),
HasTextImage = MAX(CASE WHEN si.IndID IN ( 255) THEN 1 ELSE 0 END),
HasClustered = MAX(CASE WHEN si.IndID IN ( 1 ) THEN 1 ELSE 0 END)
FROM dbo.SysObjects so,
dbo.SysIndexes si,
(--Derived table finds page size in KB according to system type
SELECT Low/1024 AS PageKB --1024 is a binary Kilo-byte
FROM Master.dbo.spt_Values
WHERE Number = 1 --Identifies the primary row for the given type
AND Type = 'E' --Identifies row for system type
) pkb
WHERE si.ID = so.ID
AND si.IndID IN (0, --Table w/o Text or Image Data
1, --Table with clustered index
255) --Table w/ Text or Image Data
AND so.XType = 'U' --User Tables
AND PERMISSIONS(so.ID) <> 0
GROUP BY so.Name,
so.UID,
so.ID,
pkb.PageKB
ORDER BY ReservedKB DESC
答案 3 :(得分:-1)
“ dtproperties ”和“ sysdiagrams ”怎么样? 这些表将显示为用户表不正确