我正在测试,它将检查对象是否已保存到数据库中。测试将用唯一值保存对象,然后我要从数据库中获取该对象并检查其是否不为null。 ID是自动生成的,因此我需要按名称查找此对象。
我的测试如下:
@Test
public void shouldAddNewEmployee(){
String firstNameTest = "Jon";
String lastNameTest = "Doe";
double salary1test = 10.0;
String salary2test = "10.00";
String localityTest = "LosAngeles";
String zipCodeTest = "00-000";
String streetTest = "LosAngeles str.";
int streetNumberTest = 10;
Employee testEmployee = new Employee(
firstNameTest,
lastNameTest,
salary1test,
salary2test,
localityTest,
zipCodeTest,
streetTest,
streetNumberTest);
EmployeeRepository.addNewEmployeeFromCLI(testEmployee);
String customQueryFindJonDoe = "select e from Employee e where e.firstName = Jon and e.lastName = Doe";
EntityManager entityManager = JPAUtils.openEntityManager();
List<Employee> foundJonDoe = entityManager.createQuery(customQueryFindJonDoe).getResultList();
Assertions.assertNotEquals(null, foundJonDoe);
if (entityManager.isOpen()) {
entityManager.close();
}
}
运行后出现错误:
起因:com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:“ where子句”中的未知列“ Jon”
此查询的外观如何?
答案 0 :(得分:2)
您必须在查询中设置参数:
String customQueryFindJonDoe =
"select e from Employee e where e.firstName = :firstname and e.lastName = :lastName";
EntityManager entityManager = JPAUtils.openEntityManager();
TypedQuery<Employee> q = entityManager.createQuery(customQueryFindJonDoe, Employee.class);
q.setParameter("firstname", "Jon");
q.setParameter("lastName", "Doe");
List<Employee> foundJonDoe = q.getResultList();
有关查询的更多信息,请参见:
https://docs.oracle.com/javaee/7/tutorial/persistence-querylanguage002.htm#BNBRG https://www.objectdb.com/java/jpa/query