Question

using (var webClient = new WebClient())
{
   string rawJSON = webClient.DownloadString("http://data.nba.net/data/10s/prod/v1/calendar.json");
   var jsonConverted = JsonConvert.DeserializeObject<NumGameByDate>(rawJSON);
}

以上是我的代码，我试图检索日期和该日期的游戏数。我已经通过NBA球队的json数据实现了这一目标，但是这一数据的格式不同。

public class NumGameByDate
{
    public _internal _internal { get; set; }
    public string startDate { get; set; }
    public string endDate { get; set; }
    public string startDateCurrentSeason { get; set; }
}

这是我的NumGameByDate类，您如何建议存储日期和游戏数。以下是JSON外观的示例。

{
"_internal": {
"pubDateTime": "2018-08-10 16:57:34.402",
"xslt": "xsl/league/schedule/marty_game_calendar.xsl",
"eventName": "_SPECIAL_ELA_EVENT_martyGameCalendar"
},
"startDate": "20171017",
"endDate": "20190410",
"startDateCurrentSeason": "20180702",
"20171017": 2,
"20171018": 11,
"20171019": 3,
"20171020": 10,
"20171021": 11,
"20171022": 3,
"20171023": 8,
"20171024": 6,
"20171025": 10,

Answer 1

我认为您根本不需要_internal部分（如果您这样做，仍然可以使用rawJson和class进行解析）。然后您可以执行以下操作：

Dictionary<string,string> myData;
using (var webClient = new WebClient())
{
    string rawJSON = webClient.DownloadString("http://data.nba.net/data/10s/prod/v1/calendar.json");
    string myJSON = "{" + rawJSON.Substring(rawJSON.IndexOf(@"""startDate"));
    myData = JsonConvert.DeserializeObject<Dictionary<string,string>>(myJSON);
}

这将跳过_internal部分，并将其余部分解析为Dictionary（尽管您可能会得到Dictionary，但我更喜欢使用string，string）。

Answer 2

好吧，如果只需一次转换文件就可以满足javascript的需求。您可能需要更自动的方法。

// Load your JSON in variable x
var x = { "someOtherProperty": { etc:true }, "20171017": 2, "20171018": 11, "20171019": 3, "20171020": 10, "20171021": 11, "20171022": 3, "20171023": 8, "20171024": 6 }
x.games = []   // create an array that will hold the converted values.
for (key in x){
    // Some regex testing if the current property is a date
    if (/[2][0][01][0-9][0-1][0-9][0-3][0-9]/.test(key)){
        x.games.push({ date: key, gameCount: x[key] }); // Put the new object in an actual array
        delete x[key] // Delete the old value
    }
}

这将导致以下JSON正确填充数组：

x = { 
     "someOtherProperty": { etc:true },
     "games":[{"date":"20171017","gameCount":2},{"date":"20171018","gameCount":11},{"date":"20171019","gameCount":3},{"date":"20171020","gameCount":10},{"date":"20171021","gameCount":11},{"date":"20171022","gameCount":3},{"date":"20171023","gameCount":8},{"date":"20171024","gameCount":6},{"date":"20171025","gameCount":10}]
}

Answer 3

鉴于所有评论，特别是跳过对一些POCO进行反序列化的评论，您可以执行以下操作：

if (chkGetMedian.Checked)
{
     $"{employee}: {formattedTime} - Employee Median = {currentEmployeeMedian} minutes";
}
else
{
    $"{employee}: {formattedTime}";
}

输出：

//Dependency JSON.Net

var obj = JObject.Parse(your_sample_json_string);
foreach (var t in obj)
{           
    DateTime d;
    if (DateTime.TryParseExact(t.Key, "yyyyMMdd", CultureInfo.InvariantCulture, DateTimeStyles.None, out d))
    {
        Console.WriteLine("{0} = {1}", d.ToShortDateString(), t.Value);
    }
}

根据需要/必要进行改进。嗯〜

从网络将JSON转换为C＃

3 个答案: