我正在一个有两个桌子的销售项目中。一个是sales_rev_asset 另一个是sales_lab。
以下是表格格式：-
sales_rev_asset：-
salesid year rev_ratio1 rev_ratio_2 ratio_3 asset_ratio1 asset_ratio_2 asset_ratio_3
10001 2016 30 12 56 78 89 90
10001 2017 13 56 87 33 95 28
10001 2018 98 84 53 62 24 48
10002 2016 33 55 62 69 78 10
10002 2017 62 17 12 14 7 9
10002 2018 28 83 45 16 35 50
sales_lab：-
salesid ratio_name col1 col2 col3
10001 lab_ratio1 1 15 54
10001 lab_ratio2 3 54 41
10001 lab_ratio3 5 98 12
10002 lab_ratio1 2 74 23
10002 lab_ratio2 8 32 36
10002 lab_ratio3 9 19 65
但我想要类似以下格式的数据：-
salesid year rev_ratio1 rev_ratio_2 ratio_3 asset_ratio1 asset_ratio_2 asset_ratio_3 lab_ratio1 lab_ratio2 lab_ratio3
10001 2016 30 12 56 78 89 90 1 3 5
10001 2017 13 56 87 33 95 28 15 54 98
10001 2018 98 84 53 62 24 48 54 41 12
10002 2016 33 55 62 69 78 10 2 8 9
10002 2017 62 17 12 14 7 9 74 32 36
10002 2018 28 83 45 16 35 50 23 36 65
请有人建议我。如何在oracle中实现上述格式。我正在使用Oracle 11g。
答案 0 :(得分：1)
根据您的问题，您需要在子查询中将ROW_NUMBER函数与 windows函数结合使用，以在sales_rev_asset表中创建行号。然后在unpivot中进行sales_lab，然后按行号join。
CREATE TABLE sales_rev_asset(
salesid INT,
year INT,
rev_ratio1 INT,
rev_ratio_2 INT,
ratio_3 INT,
asset_ratio1 INT,
asset_ratio_2 INT,
asset_ratio_3 INT
);
INSERT INTO sales_rev_asset VALUES (10001,2016,30,12,56,78,89,90);
INSERT INTO sales_rev_asset VALUES (10001,2017,13,56,87,33,95,28);
INSERT INTO sales_rev_asset VALUES (10001,2018,98,84,53,62,24,48);
INSERT INTO sales_rev_asset VALUES (10002,2016,33,55,62,69,78,10);
INSERT INTO sales_rev_asset VALUES (10002,2017,62,17,12,14,7 ,9);
INSERT INTO sales_rev_asset VALUES (10002,2018,28,83,45,16,35,50);
CREATE TABLE sales_lab(
salesid INT,
ratio_name VARCHAR(50),
col1 INT,
col2 INT,
col3 INT
);
INSERT INTO sales_lab VALUES (10001,'lab_ratio1',1,15,54);
INSERT INTO sales_lab VALUES (10001,'lab_ratio2',3,54,41);
INSERT INTO sales_lab VALUES (10001,'lab_ratio3',5,98,12);
INSERT INTO sales_lab VALUES (10002,'lab_ratio1',2,74,23);
INSERT INTO sales_lab VALUES (10002,'lab_ratio2',8,32,36);
INSERT INTO sales_lab VALUES (10002,'lab_ratio3',9,19,65);
查询1 ：
with cte as (
select t.*,ROW_NUMBER() OVER(PARTITION BY salesid ORDER BY salesid) rn
from sales_lab t
),unpivot_CTE as (
select t.SALESID,
1 RN,
(Case when t.RATIO_NAME = 'lab_ratio1' and rn = 1 then col1 end) AS lab_ratio1,
(Case when t.RATIO_NAME = 'lab_ratio2' and rn = 2 then col1 end) AS lab_ratio2,
(Case when t.RATIO_NAME = 'lab_ratio3' and rn = 3 then col1 end) AS lab_ratio3
from cte t
UNION ALL
select t.SALESID,
2 RN,
(Case when t.RATIO_NAME = 'lab_ratio1' and rn = 1 then col2 end),
(Case when t.RATIO_NAME = 'lab_ratio2' and rn = 2 then col2 end),
(Case when t.RATIO_NAME = 'lab_ratio3' and rn = 3 then col2 end)
from cte t
UNION ALL
select t.SALESID,
3 RN,
(Case when t.RATIO_NAME = 'lab_ratio1' and rn = 1 then col3 end),
(Case when t.RATIO_NAME = 'lab_ratio2' and rn = 2 then col3 end),
(Case when t.RATIO_NAME = 'lab_ratio3' and rn = 3 then col3 end)
from cte t
)
select t1.*,t2.lab_ratio1,t2.lab_ratio2,t2.lab_ratio3
from (
select t.*,ROW_NUMBER() OVER(PARTITION BY salesid ORDER BY year) rn
from sales_rev_asset t
) t1
INNER JOIN (
select
SALESID,
rn,
MAX(lab_ratio1) lab_ratio1,
MAX(lab_ratio2) lab_ratio2,
MAX(lab_ratio3) lab_ratio3
from unpivot_CTE
group by SALESID,rn
) t2 ON t1.salesid = t2.salesid and t1.rn = t2.rn
ORDER BY t1.SALESID,t1.year
Results ：
| SALESID | YEAR | REV_RATIO1 | REV_RATIO_2 | RATIO_3 | ASSET_RATIO1 | ASSET_RATIO_2 | ASSET_RATIO_3 | RN | LAB_RATIO1 | LAB_RATIO2 | LAB_RATIO3 |
|---------|------|------------|-------------|---------|--------------|---------------|---------------|----|------------|------------|------------|
| 10001 | 2016 | 30 | 12 | 56 | 78 | 89 | 90 | 1 | 1 | 3 | 5 |
| 10001 | 2017 | 13 | 56 | 87 | 33 | 95 | 28 | 2 | 15 | 54 | 98 |
| 10001 | 2018 | 98 | 84 | 53 | 62 | 24 | 48 | 3 | 54 | 41 | 12 |
| 10002 | 2016 | 33 | 55 | 62 | 69 | 78 | 10 | 1 | 2 | 8 | 9 |
| 10002 | 2017 | 62 | 17 | 12 | 14 | 7 | 9 | 2 | 74 | 32 | 19 |
| 10002 | 2018 | 28 | 83 | 45 | 16 | 35 | 50 | 3 | 23 | 36 | 65 |
答案 1 :(得分：0)
您需要使用以下代码来旋转sales_lab：
SELECT * FROM
(
SELECT salesid, ratio_name, col1
FROM sales_tab
WHERE conditions
)
PIVOT
(
MAX(col1)
FOR ratio_name
IN ( lab_ratio1, lab_ratio2, lab_ratio3)
)
这将为您提供所需的输出，然后您可以使用使用salesid的简单JOIN来按需显示数据。
答案 2 :(得分：0)
create table pivoted as
SELECT * FROM
(
SELECT salesid,2016 year, ratio_name, col1
FROM sales_lab
)
PIVOT
(
MAX(col1)
FOR ratio_name
IN ( 'lab_ratio1' lab_ratio1, 'lab_ratio2' lab_ratio2, 'lab_ratio3' lab_ratio3)
)
union
SELECT * FROM
(
SELECT salesid,2017 year, ratio_name, col2
FROM sales_lab
)
PIVOT
(
MAX(col2)
FOR ratio_name
IN ( 'lab_ratio1' lab_ratio1, 'lab_ratio2' lab_ratio2, 'lab_ratio3' lab_ratio3)
)
union
SELECT * FROM
(
SELECT salesid,2018 year, ratio_name, col3
FROM sales_lab
)
PIVOT
(
MAX(col3)
FOR ratio_name
IN ( 'lab_ratio1' lab_ratio1, 'lab_ratio2' lab_ratio2, 'lab_ratio3' lab_ratio3)
);
select
s.salesid,
s.year,
s.rev_ratio1,
s.rev_ratio_2,
s.ratio_3,
s.asset_ratio1,
s.asset_ratio_2,
s.asset_ratio_3,
p.lab_ratio1,
p.lab_ratio2,
p.lab_ratio3
from
sales_rev_asset s
join
pivoted p
on
s.salesid = p.salesid and
s.year = p.year
order by
s.salesid,
s.year;
输出：
SALESID YEAR REV_RATIO1 REV_RATIO_2 RATIO_3 ASSET_RATIO1 ASSET_RATIO_2 ASSET_RATIO_3 LAB_RATIO1 LAB_RATIO2 LAB_RATIO3
---------- ---------- ---------- ----------- ---------- ------------ ------------- ------------- ---------- ---------- ----------
10001 2016 30 12 56 78 89 90 1 3 5
10001 2017 13 56 87 33 95 28 15 54 98
10001 2018 98 84 53 62 24 48 54 41 12
10002 2016 33 55 62 69 78 10 2 8 9
10002 2017 62 17 12 14 7 9 74 32 19
10002 2018 28 83 45 16 35 50 23 36 65