我想将两个BigInt数字相除,并得到一些有效数字和一个指数的结果。到目前为止,我已经知道了:
f = (numerator, denominator, significantsLength) => {
const denominatorLength = ('' + denominator).length
const extension = significantsLength + denominatorLength
const extendedNumerator = numerator * 10n ** BigInt(extension)
const div = extendedNumerator / denominator
const divLength = ('' + div).length
const digitsSurplus = divLength - significantsLength
const significants = div / 10n ** BigInt(digitsSurplus)
const exponent = digitsSurplus - extension
return significants + 'e' + exponent
}
所以f(1n,3n,3)
产生'333e-3'
会更好吗?此代码不舍入。零和负数也不能很好地工作。