Question

我有一个表单，可以用鼠标在其中移动标签。我想做的是确保不要将一个标签移到另一个控件使用的空间中。

是否有比我在下面使用的方法更好，更有效的方法：

for each c as control in me.controls
  if c.location.x > testcontrol.location.x and c.location.x < testcontrol.location.x + testcontrol.height and c.location.y > testcontrol.location.y and c.location.y < testcontrol.location.y + testcontrol.width then
     'testcontrol shares space with control c
     <do stuff>
   End if
next

我发现上述内容过于笨重，难以理解/阅读。只是希望有一些VB魔术可以更有效地做到这一点。

从我的搜索中，我看到C＃具有“ intersectswith”功能，但似乎找不到VB的类似功能。此post显示了vs使用intersectwith的方法，但是我无法将其用于我的工作。也许是其他版本的VB？

Answer 1

您忘记添加Bounds：

// c++ test ConsoleApplication2.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
using namespace std;
#include<iostream>
#include<vector>    
#include<unordered_set>
#include "c++ test ConsoleApplication2.h"//this file only contain one line"#pragma once"

std::unordered_set<std::unique_ptr<Employee >>  scanned_set;
std::unordered_set<std::unique_ptr<Employee >> to_scan_set;

int countt;



// Employee info
class Employee {
public:
    int getImportance(vector<std::unique_ptr<Employee >>  employees, int id)
    {
        for (auto it = employees.begin(); it != employees.end(); ++it)
        {
            if ((*it)->id == id)
            {
                countt += (*it)->importance;
                std::unique_ptr<Employee > testPointer(new Employee(1, 2,  vector<int>()));
                scanned_set.insert(testPointer); //error occurs here

                scanned_set.insert(*it);
                if (!(*it)->subordinates.empty())
                {
                    for (auto to_scan_iterator = to_scan_set.begin(); to_scan_iterator != to_scan_set.end(); ++to_scan_iterator) {
                        to_scan_set.insert((*to_scan_iterator));
                    }
                    return  getImportance();
                }

            }
        }
    }


    int getImportance();

    Employee(int id, int importance, vector<int>& subordinates) {
        this->id = id;
        this->importance = importance;
        this->subordinates = subordinates;
    }
    // It's the unique ID of each node.
    // unique id of this employee
    int id;
    // the importance value of this employee
    int importance;
    // the id of direct subordinates
    vector<int> subordinates;
};

inline int Employee::getImportance()
{
    if (to_scan_set.empty())
    {
        return 0;
    }
    else
    {
        for (auto it = to_scan_set.begin(); it != to_scan_set.end(); ++it)
        {
            if (scanned_set.find((*it)) == to_scan_set.end())
            {
                countt += (*it)->importance;
                scanned_set.insert(*it);
                if (!(*it)->subordinates.empty())
                {
                    for (auto to_scan_iterator = to_scan_set.begin(); to_scan_iterator != to_scan_set.end(); ++to_scan_iterator)
                    {
                        if (scanned_set.find((*it)) == to_scan_set.end())
                        {
                            to_scan_set.insert((*to_scan_iterator));
                        }
                        return  getImportance();
                    }

                }
            }
        }
    }
}

IntersectsWith不是Control的方法，而是Rectangle的方法。

VB.NET确定一个控件是否与另一个控件共享空间

1 个答案: