Question

我有一个postgres查询，用于从表“ like”中获取数据

代码为

$query = 'select * from like  where (discovery=? and user=?);';
$res = pg_query_params($query, array($_POST['discovery_id'], $_POST['user_id']));

但是在执行时却给出错误

<b>Warning</b>:  pg_query_params(): Query failed: ERROR:  syntax error at or near "where"
LINE 1: select * from like  where (discovery=? and user=?);
                        ^ in

如何正确执行此查询？我还有另一个名为发现和用户的表。这可能是问题吗？

Answer 1

尝试

import abc


class BasePlot(metaclass=abc.ABCMeta):

    @abc.abstractmethod  # this ensures that BasePlot cannot be instantiated
    def __init__(self, **kwargs):
        self.parameters = kwargs
        self.figsize = None  # in your example, you use figsize only in __call__
        self.nrows = None  # declare your instance attributes in the cunstructor
        self.ncols = None  # declare your instance attributes in the cunstructor
        self.setparams()  # I would probably add this to __call__ instead of having it here


    def setparams(self):
        if 'font' not in self.parameters.keys():
            self.parameters['font'] = 'serif'
        if 'cycle' not in self.parameters.keys():
            self.parameters['cycle'] = self.cycle('0')
        if 'linestyles' not in self.parameters.keys():
            self.parameters['linestyles'] = "paper"
        if 'scheme' not in self.parameters.keys():
            self.parameters['scheme'] = 'nb'
        if 'linestyle' not in self.parameters.keys():
            self.parameters['linestyle'] = "ls2"


    def cycle(self, n: str):
        # this is just a stub method, let it do whatever you need it to do
        if n == '0':
            return "cycle is 1"
        elif n == '1':
            return "cycle is 2"


    def __call__(self, nrows, ncols, figsize=(9, 6)):
        self.nrows = nrows
        self.ncols = ncols
        self.figsize = figsize
        # this is just a stub method, let it do whatever you need it to do
        print(self.parameters)
        return self.nrows, self.ncols, self.figsize


class DefaultPlot(BasePlot):

    def __init__(self, **kwargs):  # needed here because the contract requires __init__ to be implemented
        super().__init__(**kwargs)


class Standard(DefaultPlot):
    pass


def main():

    print(Standard(**{'scheme': 'vega'})(1, 1))
    print("="*20)
    print(DefaultPlot(**{'scheme': 'vega'})(1, 1, figsize=(9.5, 4.5)))


if __name__ == '__main__':
    main()

# Output:
# {'scheme': 'vega', 'font': 'serif', 'cycle': 'cycle is 1', 'linestyles': 'paper', 'linestyle': 'ls2'}
# (1, 1, (9, 6))
# ====================
# {'scheme': 'vega', 'font': 'serif', 'cycle': 'cycle is 1', 'linestyles': 'paper', 'linestyle': 'ls2'}
# (1, 1, (9.5, 4.5))

Postgres查询在“ where”处或附近给出语法错误

1 个答案: