我对c ++并不了解。
我已经实现了智能指针,以防止由原始指针引起的问题。 (内存泄漏)
下面是智能指针的代码。
#ifndef SMARTPOINTER
#define SMARTPOINTER
class RC
{
private:
int count; // Reference count
public:
RC(){ count = 0; }
void AddRef()
{
// Increment the reference count
count++;
}
int Release()
{
// Decrement the reference count and
// return the reference count.
if(count==0) return 0;
return --count;
}
};
template < typename T > class SP
{
private:
T* pData; // pointer
RC* reference; // Reference count
public:
SP() : pData(0), reference(0)
{
// Create a new reference
reference = new RC();
// Increment the reference count
reference->AddRef();
}
SP(T* pValue) : pData(pValue), reference(0)
{
// Create a new reference
reference = new RC();
// Increment the reference count
reference->AddRef();
}
SP(const SP<T>& sp) : pData(sp.pData), reference(sp.reference)
{
// Copy constructor
// Copy the data and reference pointer
// and increment the reference count
reference->AddRef();
}
~SP()
{
// Destructor
// Decrement the reference count
// if reference become zero delete the data
if(reference->Release() == 0)
{
delete pData;
delete reference;
}
}
T& operator* ()
{
return *pData;
}
T* operator-> ()
{
return pData;
}
SP<T>& operator = (const SP<T>& sp)
{
// Assignment operator
if (this != &sp) // Avoid self assignment
{
// Decrement the old reference count
// if reference become zero delete the old data
if(reference->Release() == 0)
{
delete pData;
delete reference;
}
// Copy the data and reference pointer
// and increment the reference count
pData = sp.pData;
reference = sp.reference;
reference->AddRef();
}
return *this;
}
};
#endif // SMARTPOINTER
我的问题正在关注..
如下使用此智能指针类
SP<MyObject> ptrObject; //MyObject class is the custom class.
MyObject *ptr = new MyObject;
ptrObject = ptr; //This invokes the SP(T *) constructor.. why?
//Though operator = ( T*) is not defined.
这时,尽管未定义operator=(T*)
函数,为什么要调用智能指针SP(T * pValue)的构造函数?
我以为创建类对象时会调用构造函数。
请解释一下,谢谢。
答案 0 :(得分:1)
每当在上下文中使用某种T1类型的表达式但不接受该类型但接受某种其他T2类型的表达式时,就会执行隐式转换; 特别是: