Question

我正在使用excel为我的测试自动化脚本输入数据，当我知道要读取的确切行和列时，便可以从excel读取数据。我面临的挑战是在工作表中合并单元格时。例如。 Test data excel sample

这里ScriptName和Iteration是我的主键，用于标识脚本的唯一数据集。所以我的问题是：

我想获取有关ScriptName的所有ReferenceSetName，并进行迭代（即，对于登录脚本而言，迭代1）：我必须获取ABC1引用集，ABC2引用集，ABC3引用集
我想获取有关ScriptName，Iteration和ReferenceSet的所有PackageName，即对于登录脚本，Iteration 1，ReferenceSet ABC1引用集：我必须获取ABC1，ABC2，ABC3 < / li>

当前下面是方法-getEntireCellValue（）我正在用来从excel提取数据，我需要帮助来解决上述2个问题。真的很感谢任何支持。

public void getExcelRowNum() {
    boolean found = false;
    String scriptCell = null, iterationCell = null;
    try {
        @SuppressWarnings("rawtypes")
        Iterator iterator = sheet.rowIterator();
        while (iterator.hasNext()) {
            Row row = (Row) iterator.next();
            scriptCell = row.getCell(1).toString().trim();
            iterationCell = row.getCell(2).toString().trim();
            if (row.getCell(2).getCellTypeEnum() == CellType.NUMERIC)
                iterationCell = iterationCell.substring(0, iterationCell.indexOf(".")).trim();
            if ((scriptCell.equals(scriptName) && iterationCell.equals(String.valueOf(iteration).trim()))
                    || (scriptCell.equals(scriptName) && Integer.parseInt(iterationCell) == iteration)) {
                rowNum = row.getRowNum();

                found = true;
                break;
            }
        }
        if (rowNum == -1 || found == false)
            throw new Exception("Please check the test name: " + scriptName + " or the iteration: " + iteration
                    + " in the test data sheet");

        row = sheet.getRow(0);
    }
    catch (Exception e) {
        e.printStackTrace();
    }
}

public void getExcelColNum(String colName) {
    boolean found = false;
    try {
        for (int i = 0; i < row.getLastCellNum(); i++) {
            if (row.getCell(i).getStringCellValue().trim().equals(colName.trim())) {
                col_Num = i;
                found = true;
                break;
            }
        }
        if (col_Num == -1 || found == false)
            throw new Exception("Please check the column name: " + colName + " in the test data sheet");
    }
    catch (Exception e) {
        e.printStackTrace();
    }
}

public void getCell() {
    try {
        row = sheet.getRow(rowNum);
        cell = row.getCell(col_Num);
    }
    catch (Exception e) {
        e.printStackTrace();
    }
}

    //Prior to calling this method. I am connecting to the excel sheet which 
    is in .xlsx or xls format
    public String getEntireCellValue(String sheetName, String colName) {
            try {
                sheet = workbook.getSheet(sheetName);           
                getExcelRowNum();
                getExcelColNum(colName);
                getCell();
                if (cell.getCellTypeEnum() == CellType.STRING)
                    return cell.getStringCellValue().trim();
                else if (cell.getCellTypeEnum() == CellType.BLANK)
                    return null;
            }
            catch (Exception e) {
                e.printStackTrace();
                return null;
         }
    }

    public int getNumOfMergedRows() {
        int rowsMerged = 0;
        try {
            for(int i = 0; i < sheet.getNumMergedRegions(); i++) {
                CellRangeAddress range = sheet.getMergedRegion(i);
                if (range.getFirstRow() <= rowNum && range.getLastRow() >= 
                rowNum) {
                    ++rowsMerged;
                }
            }
            System.out.println("Number of rows merged are: " + rowsMerged);
        }
        catch (Exception e) {
            e.printStackTrace();
        }
        return rowsMerged;
    }

P.S。我在这里所做的是，我正在尝试获取脚本的合并行数，例如将6行合并为Login脚本，然后在这6行中查找单元格数以获得引用集名称（3个单元格）。注意：当我调用上述方法-getNumOfMergedRows（）来确定用于Login脚本的合并行数时，我将输出4而不是6。

Answer 1

我有一个示例代码，将字段作为输入，它将对所有值的第三列中的值进行计数并将其存储在地图中。这样做是通过计算excel文件中的空白值，然后将计数器重置为每个有效值

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;

import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.CellType;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.ss.usermodel.Workbook;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;

public class Demo {

    public static void main(String[] args) {
        readFile(new File("excelstack.xlsx"));
    }
    public static void readFile(File file) {

        try {

            FileInputStream excelFile = new FileInputStream(file);
            Workbook workbook = new XSSFWorkbook(excelFile);
            Sheet datatypeSheet = workbook.getSheetAt(0);
            Iterator<Row> iterator = datatypeSheet.iterator();

            Map<String,Integer> map=new HashMap<String,Integer>();

            int coltocheck=1;
            int counter=1;
            String currentitem="";
            while (iterator.hasNext()) {
                Row currentRow = iterator.next();
                Iterator<Cell> cellIterator = currentRow.iterator();                                              
                while (cellIterator.hasNext()) {
                    Cell currentCell = cellIterator.next();                                  
                   if(currentCell.getCellTypeEnum()==CellType.BLANK ) { 
                            if(currentCell.getColumnIndex()==coltocheck)
                                    map.put(currentitem, counter++);
                    }                    
                    else if(currentCell.getCellTypeEnum()==CellType.STRING && currentCell.getColumnIndex()==coltocheck) {
                            currentitem=currentCell.getStringCellValue();                       
                            counter=1;
                            map.put(currentitem, counter++);

                    }
                }                                                
            } 
           for(Map.Entry<String, Integer> m:map.entrySet())
               System.out.println(m.getKey()+" "+m.getValue());

        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } finally {                     
        }


    }
}

Answer 2

下面的代码将确定colName列中合并单元格的数量，起始行为startingRow

public int getNumOfMergedRows(String colName, int startingRow) {
    int rowsMerged = 0, col = 0;
    XSSFRow mergedRow = null;
    XSSFCell mergedCell = null;
    try {
        col = getExcelColNum(colName);
        for (int i = startingRow + 1; i < sheet.getPhysicalNumberOfRows(); i++) {
            mergedRow = sheet.getRow(i);
            mergedCell = mergedRow.getCell(col);
            if (mergedCell.getCellTypeEnum() == null || mergedCell.getCellTypeEnum() == CellType.BLANK)
                rowsMerged++;
            else
                break;
        }
        rowsMerged++;
    }
    catch (Exception e) {
        e.printStackTrace();
    }
    logger.info(rowsMerged + " rows are merged in columne" + colName + " for " + scriptName + " script");
    return rowsMerged;
}

如何使用apache poi确定合并单元格中的行数？

2 个答案: