我正在尝试在Angular应用程序中开发两个下拉菜单。第一个是商店清单,另一个是货仓清单。当我选择商店时,它将在数据和所选商店列表上显示它,但是当我选择货仓时,它并不会基于所选商店。
在这里,我有两个下拉框。这里有很多问题,但是我哪里都找不到正确的答案。
TypeScript文件:
ngOnInit() {
this._enqService.FetchPopulateOutlets().subscribe(outletsData => {
let allShops = {
ShopName: 'All',
ShopID: 0
}
this.outletDetails = [allShops, ...outletsData]
}, error => {
console.error(error);
this.statusMessage = "Problem with the service.Please try again after sometime";
});
this._enqService.FetchGodownPopulateOutlets().subscribe(GodownsData => {
let allGodowns = {
GodownName: 'All',
GodownId: 0
}
this.GodownDetails = [allGodowns, ...GodownsData]
}, error => {
console.error(error);
this.statusMessage = "Problem with the service.Please try again after sometime";
});
}
onSelect(shopid: number) {
this._enqService.FetchItemDetails(shopid, this.godownid, this.pageIndex).subscribe(itemsData => this.itemdetails = itemsData, error => {
console.error(error);
this.statusMessage = "Problem with the service.Please try again after sometime";
});
我的HTML:
<span>
<select class="form-control" name="outletDetail" (change)="onSelect($event.target.value)">
<option value="0" disabled>Select a Shop</option>
<option *ngFor="let outletDetail of outletDetails" [value]="outletDetail.ShopID">{{outletDetail.ShopName}}</option>
</select>
</span>
<span>
<select class="form-control" name="godowndata" (change)="onSelect($event.target.value)">
<option value="0" disabled>Select a Godown</option>
<option *ngFor="let godowndata of GodownDetails" [value]="godowndata.GodownId">{{godowndata.GodownName}}</option>
</select>
</span>
我认为问题出在Onselect上,因为在这里我使用两个参数,而在TypeScript中我仅使用一种方法。
答案 0 :(得分:1)
使用 ngModelChange
和 ngModel
<select class="form-control" [(ngModel)]="selected" name="godowndata" (ngModelchange)="onSelect(selected)">
答案 1 :(得分:0)
您可以使用 change 事件
<select [(ngModel)]="selected" name="status" placeholder="select" (change)="onOptionsSelected()">
<option *ngFor="let sta of accTypes" [ngValue]="sta">{{sta.name}}</option>
</select>