Question

我正在尝试获取视图的图像（约束布局），并通过android send-intent分享它。

我尝试了很多方法，但直到现在都没有奏效。这是我到目前为止的内容：

public void shareStatsImage(){
    constraintLayout.setDrawingCacheEnabled(true);
    Bitmap bitmap = constraintLayout.getDrawingCache();
    File path = null;
    try {
        path = saveImageToExternal(generateImageTitle(), bitmap);
    } catch (IOException e) {
        e.printStackTrace();
    }

    final Intent shareIntent = new Intent(Intent.ACTION_SEND);
    shareIntent.setType("image/png");
    final File photoFile = new File(Objects.requireNonNull(getActivity()).getFilesDir(), Objects.requireNonNull(path).getAbsolutePath());
    shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(photoFile));
    shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
    startActivity(Intent.createChooser(shareIntent, "Share image using"));
}
public static String generateImageTitle(){
    SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy-hh-mm-ss");
    return sdf.format(new Date());
}

public File saveImageToExternal(String imgName, Bitmap bm) throws IOException {
    //Create Path to save Image
    String appFolder = "test";
    File path = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES + File.separator + appFolder); //Creates app specific folder
    path.mkdirs();
    File imageFile = new File(path, imgName+".png"); // Imagename.png
    FileOutputStream out = new FileOutputStream(imageFile);
    try{
        bm.compress(Bitmap.CompressFormat.PNG, 100, out); // Compress Image
        out.flush();
        out.close();

        // Tell the media scanner about the new file so that it is
        // immediately available to the user.
        MediaScannerConnection.scanFile(getContext(),new String[] { imageFile.getAbsolutePath() }, null,new MediaScannerConnection.OnScanCompletedListener() {
            public void onScanCompleted(String path, Uri uri) {
                Log.i("ExternalStorage", "Scanned " + path + ":");
                Log.i("ExternalStorage", "-> uri=" + uri);
            }
        });
    } catch(Exception e) {
        throw new IOException();
    }
    return imageFile;
}

此解决方案存在多个问题，例如，将图片共享到gmail时出现错误消息（“附件的权限被拒绝”）。将图片上传到Google驱动器时，我只会收到“上传失败的消息”。

一件好事是这些图像似乎出现在手机的图库中，而不是通过意图共享它们时:(

感谢您的帮助！

Answer 1

将位图转换为Uri

 private Uri getImageUri(Context context, Bitmap inImage) {

    ByteArrayOutputStream bytes = new ByteArrayOutputStream();

    inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);

    String path = MediaStore.Images.Media.insertImage(context.getContentResolver(), inImage, "Image Title", null);

    return Uri.parse(path);
}

Answer 2

您可以使用 Uri 发送图片。

Option Explicit
Private Sub table_to_table()
 'Declaration
 Dim wb1 As Workbook
 Dim wb2 As Workbook
 Dim ws1 As Worksheet
 Dim ws2 As Worksheet
 Set wb1 = Workbooks.Open("C:\Documents and Settings\DON\My Documents\testingmacro2.xlsx")
 Set wb2 = Workbooks.Open("C:\Documents and Settings\DON\My Documents\testingmacro3.xlsx")
 Set ws1 = wb1.Sheets("Name") 'better to use names instead of indices
 Set ws2 = wb2.Sheets("Another name") 'if you add/remove sheets, index change occurs

 Dim res_lr As Long
 Dim lr2 As Long
 lr2 = ws2.Cells(Rows.Count, 2).End(xlUp).Row 'find last row in ws2

 Dim copyrange As Range
 Dim i As Long
 For i = 2 To lr2
    ' we only loop once, for all values in tbl2
    ' once we run out of things to add, there's no point looping further
    ' furthermore, it looks like tbl1 and tbl2 both begin on same row
      so we can loop through same value
    Set copyrange = ws2.Range(Cells(i, 2), Cells(i, 6)).Copy
    res_lr = ws2.Cells(Rows.Count, 8).End(xlUp).Row 'find last row in result tbl
    ws2.Range(Cells(res_lr, 8), Cells(res_lr, 12)).PasteSpecial xlPasteValues

    Set copyrange = ws1.Range(Cells(i, 2), Cells(i, 6)).Copy
    ' if tbl2 began in another range, simply change to i + start of data row
    ws2.Range(Cells(res_lr + 1, 8), Cells(res_lr + 1, 12)).PasteSpecial xlPasteValues

 Next i

 wb1.Close 'closes wb1 after looping, i'd leave wb2 open to display the results

End Sub

无法与Android意向共享图像

2 个答案: