Question

我想将相同的方法应用于不同的类名：

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        InputStreamReader reader = new InputStreamReader(request.getInputStream());

        String l;
        StringBuilder sb1 = new StringBuilder();
        BufferedReader br = new BufferedReader(reader);
        while (( l = br.readLine()) != null) {
            sb1.append(l);
        }
        InputStream sb2 = new ByteArrayInputStream(sb1.toString().getBytes());
        sb1.toString();
        if(sb1.indexOf("CheckStatusRequest") != -1) {
            CheckStatusRequest checkStatusRequest = (CheckStatusRequest)testXmlToObject(sb2);
            System.out.println(checkStatusRequest.getClass());
        }else if(sb1.indexOf("CheckStatusResponse") != -1) {
            CheckStatusResponse checkStatusResponse = (CheckStatusResponse)testXmlToObject1(sb2);
            System.out.println(checkStatusResponse.getClass());
        }else if(sb1.indexOf("Consequences") != -1) {
            Consequences consequences = (Consequences)testXmlToObject2(sb2);
            System.out.println(consequences.getClass());
        }else if(sb1.indexOf("SubscriptionRequest") != -1) {
            SubscriptionRequest subscriptionRequest = (SubscriptionRequest)testXmlToObject3(sb2);
            System.out.println(subscriptionRequest.getClass());
        }else if(sb1.indexOf("TerminateSubscriptionRequest") != -1) {
            TerminateSubscriptionRequest terminateSubscriptionRequest = (TerminateSubscriptionRequest)testXmlToObject4(sb2);
            System.out.println(terminateSubscriptionRequest.getClass());
        }
    }
    public CheckStatusRequest testXmlToObject(InputStream line)  {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(CheckStatusRequest.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            CheckStatusRequest object = (CheckStatusRequest)jaxbUnmarshaller.unmarshal(line);
            return object;
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return null;
    }
    public CheckStatusResponse testXmlToObject1(InputStream line)  {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(CheckStatusResponse.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            CheckStatusResponse object = (CheckStatusResponse)jaxbUnmarshaller.unmarshal(line);
            return object;
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return null;
    }

提出的解决方案有效，但是我认为该解决方案执行不佳。该方法对于每个类都以相同的方式工作，所改变的只是返回的对象的类型。基本上，对于每种开关情况，我都有相同的方法。我试图实现一种解决方案，其中将该方法声明为Object，并在将该方法称为强制转换时进行了修改，但未按预期工作，我得到了javax.xml.bind.UnmarshalException。您可以简化此代码吗？

Answer 1

您可以通过使用泛型来实现。将您的testXmlToObject更改为：

public <T> T testXmlToObject(InputStream line, Class<T> classe)  {
    try {
        JAXBContext jaxbContext = JAXBContext.newInstance(classe);
        Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
        T object = (T) jaxbUnmarshaller.unmarshal(line);
        return object;
    } catch (JAXBException e) {
        e.printStackTrace();
    }
    return null;
}

您将方法称为testXmlToObject(line, CheckStatusRequest.class)

Java中不同类型的类的相同方法

1 个答案: