单击按钮后,我想在同一页面上显示html文件。 我创建了3个按钮,当我单击它时,浏览器将根据页面加载图像。但是Chrome向我显示了一个错误:
jquery.min.js:2 Failed to load file:///C:/Users/Ksena/proj/ajax/tabs/autumn.html: Cross origin requests are only supported for protocol schemes: http, data, chrome, chrome-extension, https.
send @ jquery.min.js:2
ajax @ jquery.min.js:2
w.fn.load @ jquery.min.js:2
(anonymous) @ index.html:23
dispatch @ jquery.min.js:2
y.handle @ jquery.min.js:2
<div class="container">
<button class="summer">Summer</button>
<button class="autumn">Autumn</button>
<button class="winter">Winter</button>
<div class="output"></div>
</div>
<script>
$(document).ready(function() {
$('.summer').click(function(){
$('.output').load('./summer.html');
});
$('.autumn').click(function(){
$('.output').load('./autumn.html');
});
$('.winter').click(function(){
$('.output').load('./winter.html');
});
});
</script>