使用SQL创建ID X-ref表

Question

使用SQL，我试图将关联在一起的ID分组在一起。对于每个关联的ID组，我需要将最小值保留为组ID，然后将组中所有不同的值列为唯一ID。输入数据按以下顺序显示，并且相关的ID始终位于相邻的行上。

--SAMPLE INPUT DATA  
CREATE TEMPORARY TABLE INPUT_TBL  
  (ID1  INTEGER,  
   ID2  INTEGER);  

INSERT INTO INPUT_TBL (ID1,ID2) SELECT 101,105;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 105,102;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 102,105;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 204,210;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 210,203;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 203,210;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 301,302;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 302,303;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 303,307;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 307,305;  
INSERT INTO INPUT_TBL (ID1,ID2) SELECT 305,307;

输入文件

Id-1 Id-2  
101  105  
105  102  
102  105  
204  210  
210  203  
203  210  
301  302  
302  303  
303  307  
307  305  
305  307  

所需的输出：

Group Id    Unq Id  
101         101  
101         105  
101         102  
203         204  
203         210  
203         203  
301         301  
301         302  
301         303  
301         307  
301         305  

Answer 1

您可以这样做：

with ids as
(
Select Id1 as ID from INPUT_TBL
union 
Select Id2 as ID from INPUT_TBL
),
iGroups as 
(
select cast(id/100 as int) as iGroup, min(ID) as groupID
from ids
group by cast(id/100 as int)
)
select ig.GroupID, ids.id as UnqID
from ids 
inner join iGroups ig on cast(ids.id/100 as int) = ig.iGroup
order by ig.GroupID, ids.id;