我之前曾问过这个问题,但我仍然无法解决,无法在SQL查询中放置参数。
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (p1, p2, p3)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm = cmd.CreateParameter("p1", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p1").Value = 1
Set prm = cmd.CreateParameter("p2", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p2").Value = 2
Set prm = cmd.CreateParameter("p3", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p3").Value = 3
cmd.Execute
conn.Close
End Function
我正在excel-2010内部使用VBA,并且正在对计算机上的外部excel文件运行查询。我得到的参数太少,预计会出现三个错误。
请注意,如果值是字符串文字,则此代码有效,因此问题出在参数上。
答案 0 :(得分:1)
您没有听从昨天的回复:(您不需要该Prm变量,但是如果使用了它,则应该使用一个作为参数。
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm1 As ADODB.Parameter
Dim prm2 As ADODB.Parameter
Dim prm3 As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (?, ?, ?)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm1 = cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append prm1
cmd.Parameters("@p1").Value = 1
Set prm2 = cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append prm2
cmd.Parameters("@p2").Value = 2
Set prm3 = cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters.Append prm3
cmd.Parameters("@p3").Value = 3
您根本不需要这些prm1,prm2,prm3:
'Set paramters in SQL query
cmd.Parameters.Append cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters("@p1").Value = 1
cmd.Parameters("@p2").Value = 2
cmd.Parameters("@p3").Value = 3
答案 1 :(得分:0)
以@@开头的名称参数,以'@'开头
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (@p1, @p2, @p3)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm = cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p1").Value = 1
Set prm = cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p2").Value = 2
Set prm = cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p3").Value = 3
cmd.Execute
conn.Close
End Function