Question

我正在尝试创建喜欢帖子的API。这适用于喜欢帖子但是在添加return HttpResponse/Response语句时出现错误：

AttributeError at /api/posts/like/4/
'HttpResponse' object has no attribute 'model'
Request Method: GET
Request URL: http://127.0.0.1:8000/api/posts/like/4/
Django Version: 2.0.7

views.py

class LikeDetailAPIView(RetrieveAPIView):
    serializer_class = PostSerializer

    def get_queryset(self):
        user = self.request.user
        post_id = self.kwargs['pk']
        like = Like(post=Post.objects.get(id=post_id), user=user)
        user_like = Like.objects.filter(post=post_id, user=user)

        if user_like.exists():
            user_like.delete()
            content = {'message': 'unliked'}
            return Response(content, status=status.HTTP_202_ACCEPTED)
         else:
            like.save()
            content = {'message': 'like'}
            return Response(content, status=status.HTTP_202_ACCEPTED)

urls.py

url(r'^like/(?P<pk>.+)/$',LikeDetailAPIView.as_view(), name='likeapi'),

我打算做的是返回一条成功消息。

serializer.py

class LikeListSerializer(serializers.ModelSerializer):
    class Meta:
       model = Like
       fields = [
            'user',
            'post',
            'time',
       ]

我可以参考任何链接吗？

Answer 1

来自官方DRF doc，

get_queryset(self) 方法返回应用于列表视图的queryset，并且应该用作 detail views 中查找的基础。默认值返回由queryset属性指定的查询集。

根据您的评论，我了解到，访问API（详细视图）时需要显示一些响应。

由于您使用的是 RetrieveAPIView 类，因此必须覆盖 retrieve() 方法，如

from rest_framework.generics import RetrieveAPIView


class LikeDetailAPIView(RetrieveAPIView):
    serializer_class = PostSerializer

    def get_queryset(self):
        return Like.objects.filter(post=self.kwargs['pk'], user=self.request.user)

    def retrieve(self, request, *args, **kwargs):
        if self.get_queryset().exists():
            self.get_queryset().delete()
            content = {'message': 'unliked'}
            return Response(content, status=status.HTTP_202_ACCEPTED)
        like = Like(post=Post.objects.get(id=post_id), user=user)
        like.save()
        content = {'message': 'like'}
        return Response(content, status=status.HTTP_202_ACCEPTED)

现在，您可以通过 HTTP GET 方法

访问端点 /api/posts/like/4/

Django：RetrieveAPIView中的HttpResponse提供AttributeError

views.py

urls.py

serializer.py

1 个答案: