由于缺乏在pyspark / python中编写代码的知识,我决定在spark.sql中编写查询。我用两种格式编写了查询。第一种格式允许EOL中断。但是,以这种格式,我会看到错误,如下所示:
results5 = spark.sql("SELECT\
appl_stock.Open\
,appl_stock.Close\
FROM appl_stock\
WHERE appl_stock.Close < 500")
以上格式会产生以下错误:
---------------------------------------------------------------------------
Py4JJavaError Traceback (most recent call last)
~/spark-2.1.0-bin-hadoop2.7/python/pyspark/sql/utils.py in deco(*a, **kw)
62 try:
---> 63 return f(*a, **kw)
64 except py4j.protocol.Py4JJavaError as e:
~/spark-2.1.0-bin-hadoop2.7/python/lib/py4j-0.10.4-src.zip/py4j/protocol.py in get_return_value(answer, gateway_client, target_id, name)
318 "An error occurred while calling {0}{1}{2}.\n".
--> 319 format(target_id, ".", name), value)
320 else:
Py4JJavaError: An error occurred while calling o19.sql.
: org.apache.spark.sql.catalyst.parser.ParseException:
mismatched input '.' expecting {<EOF>, ',', 'FROM', 'WHERE', 'GROUP', 'ORDER', 'HAVING', 'LIMIT', 'LATERAL', 'WINDOW', 'UNION', 'EXCEPT', 'MINUS', 'INTERSECT', 'SORT', 'CLUSTER', 'DISTRIBUTE'}(line 1, pos 35)
== SQL ==
SELECT appl_stock.Open appl_stock.CloseFROM appl_stockWHERE appl_stock.Close < 500
-----------------------------------^^^
at org.apache.spark.sql.catalyst.parser.ParseException.withCommand(ParseDriver.scala:197)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser.parse(ParseDriver.scala:99)
at org.apache.spark.sql.execution.SparkSqlParser.parse(SparkSqlParser.scala:45)
at org.apache.spark.sql.catalyst.parser.AbstractSqlParser.parsePlan(ParseDriver.scala:53)
at org.apache.spark.sql.SparkSession.sql(SparkSession.scala:592)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:244)
at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
at py4j.Gateway.invoke(Gateway.java:280)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:214)
at java.lang.Thread.run(Thread.java:748)
During handling of the above exception, another exception occurred:
ParseException Traceback (most recent call last)
<ipython-input-38-4920f7e68c0e> in <module>()
----> 1 results5 = spark.sql("SELECT appl_stock.Open appl_stock.CloseFROM appl_stockWHERE appl_stock.Close < 500")
~/spark-2.1.0-bin-hadoop2.7/python/pyspark/sql/session.py in sql(self, sqlQuery)
539 [Row(f1=1, f2=u'row1'), Row(f1=2, f2=u'row2'), Row(f1=3, f2=u'row3')]
540 """
--> 541 return DataFrame(self._jsparkSession.sql(sqlQuery), self._wrapped)
542
543 @since(2.0)
~/spark-2.1.0-bin-hadoop2.7/python/lib/py4j-0.10.4-src.zip/py4j/java_gateway.py in __call__(self, *args)
1131 answer = self.gateway_client.send_command(command)
1132 return_value = get_return_value(
-> 1133 answer, self.gateway_client, self.target_id, self.name)
1134
1135 for temp_arg in temp_args:
~/spark-2.1.0-bin-hadoop2.7/python/pyspark/sql/utils.py in deco(*a, **kw)
71 raise AnalysisException(s.split(': ', 1)[1], stackTrace)
72 if s.startswith('org.apache.spark.sql.catalyst.parser.ParseException: '):
---> 73 raise ParseException(s.split(': ', 1)[1], stackTrace)
74 if s.startswith('org.apache.spark.sql.streaming.StreamingQueryException: '):
75 raise StreamingQueryException(s.split(': ', 1)[1], stackTrace)
ParseException: "\nmismatched input '.' expecting {<EOF>, ',', 'FROM', 'WHERE', 'GROUP', 'ORDER', 'HAVING', 'LIMIT', 'LATERAL', 'WINDOW', 'UNION', 'EXCEPT', 'MINUS', 'INTERSECT', 'SORT', 'CLUSTER', 'DISTRIBUTE'}(line 1, pos 35)\n\n== SQL ==\nSELECT appl_stock.Open appl_stock.CloseFROM appl_stockWHERE appl_stock.Close < 500\n-----------------------------------^^^\n"
以下代码产生成功的结果,请参见下文:
results6 = spark.sql("SELECT appl_stock.Open ,appl_stock.Close FROM appl_stock WHERE appl_stock.Close < 500")
有人可以让我知道为什么第一个代码不起作用,而第二个代码为什么起作用吗?
欢呼
答案 0 :(得分:2)
因为您在第一个中使用了\
,并且将其作为奇数语法传递给spark。如果要编写多行SQL语句,请使用三引号:
results5 = spark.sql("""SELECT
appl_stock.Open
,appl_stock.Close
FROM appl_stock
WHERE appl_stock.Close < 500""")
答案 1 :(得分:0)
错误消息准确地解释了发生了什么。 FROM
和WHERE
关键字前没有空格。
例如,如果您具有以下数据框:
df = spark.createDataFrame([(490, 495), (499, 505), (510, 499)], ["Open", "Close"])
df.show()
#+----+-----+
#|Open|Close|
#+----+-----+
#| 490| 495|
#| 499| 505|
#| 510| 499|
#+----+-----+
df.createOrReplaceTempView("appl_stock")
如果您更改了代码以在每个\
前添加一个空格:
results5 = spark.sql("SELECT \
appl_stock.Open \
,appl_stock.Close \
FROM appl_stock \
WHERE appl_stock.Close < 500")
result5.show()
#+----+-----+
#|Open|Close|
#+----+-----+
#| 490| 495|
#| 510| 499|
#+----+-----+
答案 2 :(得分:0)
就我而言,我遇到了错误mismatched input '*' expecting <EOF>
。然后我意识到我正在使用spark.table(
而不是spark.sql(
。我认为这对某人可能有用...
答案 3 :(得分:0)
如果出现类似|的多余字符,则会引发类似的错误消息在SQL查询字符串中。
答案 4 :(得分:0)
怪诞的是,如果我用;
终止了我的SQL语句,这对我来说是抛出的。只需将其修复即可。
即
spark.sql("""
SELECT * FROM foo WHERE bar = 3;
""")
休息。
spark.sql("""
SELECT * FROM foo WHERE bar = 3
""")
没有。
答案 5 :(得分:0)
另一个令人惊讶的情况:我收到了同样风格的错误,即 mismatched input 'from' expecting <EOF>
。我的查询包含一个参数,但我忘记解析它(请注意缺少初始 f
):
# failing query
my_qry = """
create table my_tab as
select columns
from source_tab
where somecolumn < {parameter}
"""
spark.sql(qry_defaults).collect()
所以解决方案是正确解析参数(注意初始的f
):
# correct query
my_qry = f"""
create table my_tab as
select columns
from source_tab
where somecolumn < {parameter}
"""
spark.sql(qry_defaults).collect()
总而言之,就我而言,错误与缺少 EOF 无关。我希望有人觉得这有帮助。