Question

我想使用DQL在SQLite中进行此查询

//// src/Repository/PostRepository.php
public function hasPreviousPost($id,$slug): array
{

    $em = $this->getEntityManager();

    $query = $em->createQuery('SELECT p FROM App\Entity\Post p WHERE p.id < '.$id.' AND p.slug = '.$slug);
    $posts = $query->getResult();


    return $posts;
}

我像这样从PostController调用此函数

//// src/Controller/PostController.php
        $posts = $this->getDoctrine()->getRepository(Post::class)->findAll();

        foreach ($posts as $post){

        $hasPreviousPost = $this->getDoctrine()->getRepository(Post::class)->hasPreviousPost($post->id(),$post->Slug());
        }

但是当我运行代码时，出现此错误 “ [语义错误]第0行，'pizza-mia'附近的col 48：错误：'pizza'未定义。”

$ slug包含的比萨饼是一个字符串。

这是我的Post实体。

    <?php

namespace App\Entity;

use Doctrine\ORM\Mapping as ORM;

$countPosts = 0;

/**
 * @ORM\Entity(repositoryClass="App\Repository\PostRepository")
 * @ORM\Table(name="post")
 */
class Post
{

/**
 * @ORM\Column(type="integer")
 * @ORM\Column(unique=true)
 */
private $id;

/**
 * @ORM\Id
 * @ORM\Column(type="text")
 * @ORM\Column(unique=true)
 */
private $postId;

/**
 * @ORM\Column(type="text")
 */
private $slug;

/**
 * @ORM\Column(type="text")
 */
private $message;

/**
 * @ORM\Column(type="boolean",nullable=true)
 */
private $isScheduled;

/**
 * @ORM\Column(type="integer")
 */
private $scheduledPublishTime;


function __construct($postId,$slug,$message)
{
    global $countPosts;
    $countPosts++;
    $this->postId=$postId;
    $this->id=$countPosts;
    $this->slug=$slug;
    $this->message=$message;
    $this->isScheduled=false;
    $this->scheduledPublishTime=0;
}


public function PostId(): ?string
{
    return $this->postId;
}

public function id(): ?int
{
    return $this->id;
}


public function Slug(): ?string
{
    return $this->slug;
}


public function Message(): ?string
{
    return $this->message;
}


public function IsScheduled(): ?bool
{
    return $this->isScheduled;
}

public function changeIsScheduled(?bool $isScheduled): self
{
    $this->isScheduled = $isScheduled;

    return $this;
}

public function ScheduledPublishTime(): ?int
{
    return $this->scheduledPublishTime;
}

public function changeScheduledPublishTime(int $scheduledPublishTime): self
{
    $this->scheduledPublishTime = $scheduledPublishTime;

    return $this;
}
}

任何帮助将不胜感激。

Answer 1

以这种方式尝试。

$query = $em->createQuery('SELECT p FROM App\Entity\Post p WHERE p.id < :id AND p.slug = :slug');
$query->setParameter('id', $id);
$query->setParameter('slug', $slug);

:id和:slug代表命名参数

我的强烈假设是，您只是缺少''来将$ slug定义为查询中的字符串。但是，使用上述类似的参数也会使其更具可读性。

在documentation

中找到有关命名或编号参数的说明

Symfony / Doctrine-QueryException-[语义错误]第0行，'pizza-mia'附近的第48列：错误：未定义'pizza'

1 个答案: