Question

我具有以下数据结构，我想按“位置”对它们进行排序。

[
  {
    "id": 52,
    "position": 2,
    "components_under_section": [
      {
       "id": 122,
       "position": 2
      },
      {
       "id": 123,
       "position": 1
      }
    ]
  },
  {
    "id": 53,
    "position": 1,
    "components_under_section": [
      {
       "id": 112,
       "position": 2
      },
      {
       "id": 113,
       "position": 1
      }
    ]
  }
]

到目前为止，这是我尝试过的操作，可以对外部对象进行排序，但不能对components_under_section进行排序。我有想念吗？预先感谢。

array.sort( (a, b) => {
  let compAPosition = a[Object.keys(a)[0]]["position"];
  let compBPosition = b[Object.keys(b)[0]]["position"];

  if(a.components_under_section.length){
    a.components_under_section.sort ( (c, d) => {
      let compCPosition = c[Object.keys(c)[0]]["position"];
      let compDPosition = d[Object.keys(d)[0]]["position"];
      return ( compCPosition > compDPosition ? 1 : ((compDPosition > compCPosition ) ? -1 : 0 ) );
    })
  }

  return ( compAPosition > compBPosition ? 1 : ((compBPosition > compAPosition ) ? -1 : 0 ) );
})

所需的输出（按components_under_section排序，然后按外部对象排序）：

[
  {
    "id": 53,
    "position": 1,
    "components_under_section": [
      {
       "id": 113,
       "position": 1
      },
      {
       "id": 112,
       "position": 2
      }
    ]
  },
  {
    "id": 52,
    "position": 2,
    "components_under_section": [
      {
       "id": 123,
       "position": 1
      },
      {
       "id": 122,
       "position": 2
      }
    ]
  }
]

Answer 1

您可以通过回调进行位置排序，然后直接对外部数组进行排序，然后对内部数组driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS); //driver.findElement(By.xpath(".//button[starts-with(@type,’submit’)]")).click(); driver.findElement(By.xpath(".//*[/html/body/div[4]/div/form/div[3]/div[2]/button']")).click();进行迭代和排序。

components_under_section

嵌套对象的排序数组

1 个答案: