关于python分裂的简单问题

Question

不确定为什么最后一次打印已关闭？请参阅具体问题的评论

 john = ['john doe', 44, 32000]

jane = ['jane doe', 23, 12000]

people = [john, jane]

for p in people: 
    #===========================================================================
    # p[0] prints "john doe" as expected
    # p[0].split() prints ['john', 'doe'] as expected
    # p[0].split()[0] prints "john" and "jane" as expected
    #===========================================================================
    for x in p[0].split():
        print('--> ', x[0]) 

    # prints "j","d" - not sure why
    # expected "john" and "jane"

Answer 1

1. p [0] .split（）返回字符串列表
2. for x in ...处理列表中的每个字符串
3. x [0]因此是字符串
中的第一个字符

你可能想要摆脱'x'之后的下标。

Answer 2

像这样使用

for p in people: 
    #===========================================================================
    # p[0] prints "john doe" as expected
    # p[0].split() prints ['john', 'doe'] as expected
    # p[0].split()[0] prints "john" and "jane" as expected
    #===========================================================================
    for x in p.split():
        print('--> ', x) 

Answer 3

如你所说，p [0] .split（）给你['john'，'doe']。在你的循环中，x又指向该列表的元素“john”和“doe”。 x [0]指的是其中任何一个中的第一项 - 字符串中的第一个字符。