我有以下表格,并与Laravel关系建立查询。在我的面板中,一旦用户登录,我将获得用户详细信息和用户业务详细信息,但是现在我也不知道如何获取业务类型详细信息。
id | business_id | username | email | password
1 1 john632 john@gmail.com *******
id | user_id | business_type_id | business_name
1 1 2 Fortune
id | business_type_name | description
1 Hotel Lorem Ipsum
2 Movie Lorem Ipsum
用户
<?php
namespace App;
use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Zizaco\Entrust\Traits\EntrustUserTrait;
use App\Notifications\ResetPassword as ResetPasswordNotification;
use Laravel\Passport\HasApiTokens;
use Illuminate\Database\Eloquent\SoftDeletes;
use Webpatser\Uuid\Uuid;
use App\RoleUser;
use App\UsersBusiness;
class User extends Authenticatable
{
use Notifiable;
use EntrustUserTrait;
use HasApiTokens;
use SoftDeletes, EntrustUserTrait {
SoftDeletes::restore as sfRestore;
EntrustUserTrait::restore as euRestore;
}
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'business_id', 'username', 'email'
];
public function usersBusiness()
{
return $this->belongsTo('App\UsersBusiness', 'business_id', 'id');
}
}
UsersBusiness
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\SoftDeletes;
class UsersBusiness extends Model
{
use SoftDeletes;
/**
* The table associated with the model.
*
* @var string
*/
protected $table = 'tbl_users_business';
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'user_id', 'business_type_id', 'business_name'
];
/**
* The attributes that should be hidden for arrays.
*
* @var array
*/
protected $hidden = [
];
/**
* Dates to be treated as Carbon instances
*
* @var array
*/
public $dates = [
'deleted_at'
];
}
业务类型
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\SoftDeletes;
class BusinessTypes extends Model
{
use SoftDeletes;
/**
* The table associated with the model.
*
* @var string
*/
protected $table = 'tbl_master_business_types';
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'business_type_name', 'description'
];
/**
* The attributes that should be hidden for arrays.
*
* @var array
*/
protected $hidden = [
];
/**
* Dates to be treated as Carbon instances
*
* @var array
*/
public $dates = [
'deleted_at'
];
}
$user = Auth::user();
$data['data'] = $user->load(['usersBusiness'] => function ($query) {
$query->select(["id", "user_id", "business_name"])->get();
}]);
我得到以下响应数据:
{
"data": {
"id": 1,
"business_id": 1,
"username": "john632",
"email": "john632@gmail.com",
"password": "john632",
"users_business": {
"id": 1,
"user_id": 4,
"business_type_id": 3,
"business_name": "Honest"
},
"business_types": null
},
"token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJSUzI1NiIsImp0aSI6Ijk4YTQ5OTBmOGQxOWQ5NTg1OGFlZWU1MDY0NTBiY2Y2OWJmOWQ3NzFhZjRmN2RmMzBmMWRkZWNmNWY4OTAzM2UyNmI2MzE3MTY3MDMxOTk4In0.eyJhdWQiOiIxIiwianRpIjoiOThhNDk5MGY4ZDE5ZDk1ODU4YWVlZTUwNjQ1MGJjZjY5YmY5ZDc3MWFmNGY3ZGYzMGYxZGRlY2Y1Zjg5MDMzZTI2YjYzMTcxNjcwMzE5OTgiLCJpYXQiOjE1MzIyNjA3ODUsIm5iZiI6MTUzMjI2MDc4NSwiZXhwIjoxNTYzNzk2Nzg1LCJzdWIiOiI1Iiwic2NvcGVzIjpbXX0.f_Xv0SrtTZ9m-40oHjAglCbKv76s_bARQ74XDihhFnI-jtHKwCWiF-jai5Yt6h9QyakCTZEo1bPAJdeph7Bj0_tKJpq3sGvK4t73_LZg_OOcsmAt61a4OSAgI1pjPV0tMMwHCoHm-xLlNnriAyaLCAbTQLQkfrw53467ys6rchE5V0rzy-JswjTfmB6SvZcqXsJQo6CWDRTWYbKvJO0FSmdZfLxxO_u4i_8ah5W63qJ4MSN9q22zkZLQ-L3NZhOux2KkwWiySioL2K25Y_UZmefClYwk1h-EY_LEVht3U7Kpqn9fmM6_Q4ByD-sSzLdAixdbq4REqinSaayzfMY934nijLu7ysEIc0oIukiHYcIk9tGV6DNuQ0CWhqEn0W_308MSBU4Ffyi5SQo7ubb5uPG7l_XOdomIR9dK9KtVONbPe7iF6TuccPCWZwvqKgfFl7TqEgiUWSiAl_ekkiaUDEM3cIuIH8AOLE17UuW4W0VyR2ziIt68au8SEuP2ilMBRsRMsFGbRKQWcvLluNw_qubcdzZ4yX9kuQAvXuBrHAcXb9WMlki2votvd7RKVDwxqwsTJRoeKNtJQdEQRbRZUD6nXyzGkmtEMrfwYoLVgTX3vAgVjO_erYtI5x-NV-EnoLT352odtRDYh5gTzVbmzYAxbLf_XUCDHjvlMEvM81g",
"status": true,
"status_code": 1,
"message": "Login successfully."
}
我也想添加业务类型详细信息,所以请您指导我如何为该表添加关系。
谢谢。
答案 0 :(得分:1)
像这样在您的UserBusiness
模型中创建一个EmiratesTo关系
用户业务模型
public function businessType(){
return $this->belongsTo(BusinessType::class, 'business_type_id');
}
这样加载后
$user = Auth::user();
$user->load(['usersBusiness.businessType']); //lazy loading
dd($user);
如果仅需要userBusiness及其类型,则
dd($user->usersBusiness);
侧面说明::我认为您在用户表中不需要business_id
。只需将user_id
保留在userbusiness表中,然后在userBusness的用户模型中添加hasOne
(如果用户只能有一个业务)或hasMany
(如果用户可以有多个业务)关系。
答案 1 :(得分:0)
我建议您使用API Resources.
例如,对于我来说,我有 ChannelItemResource.php :
import re
def count(text, s):
return len(re.findall(s, text))
print(count('mama ma emu a ema ma mamu', 'ma '))
print(count('mama ma emu a ema ma mamu', 'am'))
和 ChannelResource.php :
4
2
使用此结构,您可以轻松地包含所需的关系,并且结果将以JSON形式出现。
在控制器中使用:
public function toArray($request)
{
return [
'id' => $this->id,
'channel_id' => $this->channel_id,
'channel' => $this->channel->title,
'type' => $this->type,
'description' => $this->description,
'price' => $this->price,
'created_at' => $this->created_at,
'updated_at' => $this->updated_at,
];
}