我一直在不懈地尝试从我的JAVA / Android项目到Django / Python后端创建成功的文件上传。
我要上传的文件是wav音频文件，存储在手机上。
我正在尝试混合两组代码。
我正在使用的Android代码是摘自How to upload a WAV file using URLConnection的代码。
public class curlAudioToWatson extends AsyncTask<String, Void, String> {
String asrJsonString="";
@Override
protected String doInBackground(String... params) {
String result = "";
try {
Log.d("Msg","**** UPLOADING .WAV to ASR...");
URL obj = new URL(ASR_URL);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
//conn.setRequestProperty("X-Arg", "AccessKey=3fvfg985-2830-07ce-e998-4e74df");
conn.setRequestProperty("Content-Type", "audio/wav");
conn.setRequestProperty("enctype", "multipart/form-data");
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
String wavpath=mRcordFilePath;
File wavfile = new File(wavpath);
boolean success = true;
if (wavfile.exists()) {
Log.d("Msg","**** audio.wav DETECTED: "+wavfile);
}
else{
Log.d("Msg","**** audio.wav MISSING: " +wavfile);
}
String charset="UTF-8";
String boundary = Long.toHexString(System.currentTimeMillis()); // Just generate some unique random value.
String CRLF = "\r\n"; // Line separator required by multipart/form-data.
OutputStream output=null;
PrintWriter writer=null;
try {
output = conn.getOutputStream();
writer = new PrintWriter(new OutputStreamWriter(output, charset), true);
byte [] music=new byte[(int) wavfile.length()];//size & length of the file
InputStream is = new FileInputStream (wavfile);
BufferedInputStream bis = new BufferedInputStream (is, 16000);
DataInputStream dis = new DataInputStream (bis); // Create a DataInputStream to read the audio data from the saved file
int i = 0;
copyStream(dis,output);
}
catch(Exception e){
}
conn.connect();
int responseCode = conn.getResponseCode();
Log.d("Msg","POST Response Code : " + responseCode + " , MSG: " + conn.getResponseMessage());
if (responseCode == HttpURLConnection.HTTP_OK) { //success
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
Log.d("Msg","***ASR RESULT: " + response.toString());
JSONArray jresponse=new JSONObject(response.toString()).getJSONObject("Recognition").getJSONArray("NBest");
asrJsonString=jresponse.toString();
for(int i = 0 ; i < jresponse.length(); i++){
JSONObject jsoni=jresponse.getJSONObject(i);
if(jsoni.has("ResultText")){
String asrResult=jsoni.getString("ResultText");
//ActionManager.getInstance().addDebugMessage("ASR Result: "+asrResult);
Log.d("Msg","*** Result Text: "+asrResult);
result = asrResult;
}
}
Log.d("Msg","***ASR RESULT: " + jresponse.toString());
} else {
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getErrorStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
Log.d("Msg","POST FAILED: " + response.toString());
result = "";
}
} catch (Exception e) {
Log.d("Msg","HTTP Exception: " + e.getLocalizedMessage());
}
return result; //"Failed to fetch data!";
}
@Override
protected void onPostExecute(String result) {
if(!result.equals("")){
Log.d("Msg","onPostEXECUTE SUCCESS, consuming result");
//sendTextInputFromUser(result);
//ActionManager.getInstance().addDebugMessage("***ASR RESULT: "+asrJsonString);
runOnUiThread(new Runnable() {
@Override
public void run() {
}
});
}else{
Log.d("Msg","onPostEXECUTE FAILED" );
}
}
}
public void copyStream( InputStream is, OutputStream os) {
final int buffer_size = 4096;
try {
byte[] bytes = new byte[buffer_size];
int k=-1;
double prog=0;
while ((k = is.read(bytes, 0, bytes.length)) > -1) {
if(k != -1) {
os.write(bytes, 0, k);
prog=prog+k;
double progress = ((long) prog)/1000;///size;
Log.d("Msg","UPLOADING: "+progress+" kB");
}
}
os.flush();
is.close();
os.close();
} catch (Exception ex) {
Log.d("Msg","File to Network Stream Copy error "+ex);
}
}
Django后端代码摘自：https://simpleisbetterthancomplex.com/tutorial/2016/08/01/how-to-upload-files-with-django.html，而我正在使用简单的上载：
def simple_upload(request):
if request.method == 'POST' and request.FILES['myfile']:
myfile = request.FILES['myfile']
fs = FileSystemStorage()
filename = fs.save(myfile.name, myfile)
uploaded_file_url = fs.url(filename)
return render(request, 'core/simple_upload.html', {
'uploaded_file_url': uploaded_file_url
})
return render(request, 'core/simple_upload.html')
我已经使用@csrf_exempt禁用了CSRF。
我收到错误消息“ MultiValueDictKeyError”，因为Java没有发布名称为“ myfile”的文件以供request.FILES ['myfile']捕获。已经尝试删除['myfile']并仅使用request.FILES，但随后出现错误
filename = fs.save(myfile.name, myfile)
说没有名字可取。
我可以发布文件以便被它捕获
request.FILES['myfile']
还是有更好/更简单的Django后端代码可用于与Android / IOS进行通信。
在此先感谢您，如果这是一个愚蠢的问题，我深表歉意。
答案 0 :(得分：0)
我在这里再次回答自己的问题。
我从Android:How to upload .mp3 file to http server?
找到了以下代码使用它代替How to upload a WAV file using URLConnection并更改行：dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
致dos.writeBytes("Content-Disposition: form-data; name=\"myfile\";filename=\"" + existingFileName + "\"" + lineEnd);
解决了我的问题。