我能够打印表中的所有数据，但是一个字段我无法打印

Question

我通过alamofire打电话给api，我得到了完美的响应，我能够将所有数据都放入表格单元格中的标签中，但是有一个字段无法打印，请在下面解释一下

响应：

SUCCESS: {
    data =(
        {
            "from_id" = 77;
            "from_name" = Paresh;
            image = "https://www.kwikmypay.com/mode_share/modeshare_admin/assets/images/business/userNotFound.png";
            msg = hi;
            "msg_date" = "18-07-2018 05:54:40 am";
            "msg_id" = 1;
            "new_msg" = 37;
            "to_id" = 88;
            "to_name" = Mihir;
        }

从此响应中我可以打印所有内容，但是我无法打印一个字段“ new_msg”，任何人都可以解释一下这个问题，这是我的代码

let serviceparam = ["user_id":u_id,"access_token":acc_tkn,"time_zone": currentTimeZone] as [String : Any]
        SVProgressHUD.show(withStatus: "Loading...")

        Alamofire.request(chatList, method: .post, parameters: serviceparam).responseJSON
            {
                response in

                print(response)
                let result = response.result

                if let dict = result.value as? Dictionary<String,AnyObject>{
                    if let serlist = dict["data"]{

                        self.servicelist = serlist as! [AnyObject]
                        self.tbl_chatlist.reloadData()
                        //self.dropDown.items = categorylist as! [AnyObject] as! [String]
                    }
                }
             SVProgressHUD.dismiss()
                //self.activityIndicator.stopAnimating()
        }

我的服务列表阵列已正确整理，我可以正确获取所有数据，但无法在标签上打印任何数据，请帮助我

 func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell{
        let cell = tableView.dequeueReusableCell(withIdentifier: "chatlistcell") as! ChatlistTableViewCell

         let f_name = servicelist[indexPath.row]["from_name"]
         let image = servicelist[indexPath.row]["image"]
         let date = servicelist[indexPath.row]["msg_date"]
         let newMSG = servicelist[indexPath.row]["new_msg"]
         let lastMsg = servicelist[indexPath.row]["msg"]
         cell.lblTime.text = date as? String
         cell.lblTitle.text = f_name as? String
         cell.lblMsgCount.text = newMSG as? String
         cell.lblLastMsg.text = lastMsg as? String

         let proimgurl = NSURL(string: image as! String)
         cell.img_logo.image = UIImage(data: NSData(contentsOf: proimgurl! as URL)! as Data)



        return cell
    }

这是代码，我有一个标签lblMsgCount，作为回应，有一个我无法打印的已提交的new_msg