我目前正在使用以下内容查找一个或多个单词是否在字符串中：
stopwords=set(["Good to Soft","Slow","Standard to Slow","Standard","Standard to Fast","Fast","Heavy","Soft to Heavy","Soft","Yeliding to Soft","Yeilding","Good to Yeilding","Good","Good to Firm","Firm","Hard"])
Going = stopwords.intersection(set(testtext[0].split()))
我的问题是，如果字符串中有Standard To Slow，那么交集似乎只会拾取Standard，Slow-我想要Standard To Slow。
反正我有什么可以改善的吗？
为了更清楚地说明我需要什么结果，我将使用以下示例：
我有一个活动清单
["Good to Soft","Slow","Standard to Slow","Standard","Standard to Fast","Fast","Heavy","Soft to Heavy","Soft","Yeliding to Soft","Yeilding","Good to Yeilding","Good","Good to Firm","Firm","Hard"]
我想找到这些字符串中的哪些，例如：
2:20-H布朗与儿子回收少女障碍赛（Class4）�4,094好 2m3f207y
这将返回“ good”，这就是匹配结果
2:20-H布朗与儿子回收少女障碍赛（Class4）�4,094对 软2m3f207y
这将返回“ Good to Soft”，即匹配，而不是“ Soft”
答案 0 :(得分：0)
交集只会找到匹配的元素。这是您正在比较的列表：
["Good to Soft","Slow","Standard to Slow","Standard","Standard to Fast","Fast","Heavy","Soft to Heavy","Soft","Yeliding to Soft","Yeilding","Good to Yeilding","Good","Good to Firm","Firm","Hard"]
testtext[0].split() == ["Standard", "to", "Slow"]
如果只希望它与testtext[0]中的内容匹配，则不应使用split()创建列表：
Going = stopwords.intersection({testtext[0]})