我有下表
| date | name | val | country | sex |
|------|--------|-----|---------|-----|
| 2013 | Mark | 01 | USA | M |
| 2013 | John | 02 | Germany | M |
| 2013 | Carla | 84 | Croatia | F |
| 2013 | Carlos | 49 | France | M |
| 2013 | Doe | 47 | India | M |
| 2014 | Mark | 27 | Spain | M |
| 2014 | John | 59 | Germany | M |
| 2014 | Carla | 26 | Croatia | F |
| 2014 | Carlos | 30 | France | M |
| 2014 | Doe | 49 | India | M |
| 2015 | Mark | 55 | USA | M |
| 2015 | John | 95 | Germany | M |
| 2015 | Carla | 85 | Croatia | F |
| 2015 | Carlos | 75 | France | M |
| 2015 | Doe | 65 | India | M |
| 2016 | Mark | 16 | USA | M |
| 2016 | John | 20 | Germany | M |
| 2016 | Carla | 18 | Croatia | F |
| 2016 | Carlos | 29 | France | M |
| 2016 | Doe | 35 | India | M |
| 2017 | Mark | 39 | Rusia | M |
| 2017 | John | 32 | Germany | M |
| 2017 | Carla | 21 | Croatia | F |
| 2017 | Carlos | 29 | France | M |
| 2017 | Doe | 44 | India | M |
我需要在查询中获得以下结果
| | Mark | John | Carla | Carlos | Doe |
|------|------------|--------------|--------------|-------------|------------|
| 2013 | 01/USA/M | 02/Germany/M | 84/Croatia/M | 49/France/M | 47/India/M |
| 2014 | 27/Spain/M | 20/Germany/M | 26/Croatia/M | 30/France/M | 49/India/M |
| 2015 | 55/USA/M | 95/Germany/M | 85/Croatia/M | 75/France/M | 65/India/M |
| 2016 | 16/USA/M | 20/Germany/M | 18/Croatia/M | 16/France/M | 16/India/M |
| 2017 | 39/Rusia/M | 32/Germany/M | 21/Croatia/M | 16/France/M | 16/India/M |
不要介意数据只是随机的东西。
基本上，主要分组依据是日期。
最好的问候。
答案 0 :(得分：1)
您可以使用条件聚合来执行此操作-如果您知道结果集中要使用的所有名称：
select date,
max(case when name = 'Mark' then concat_ws('/', val, country, sex) end) as Mark,
max(case when name = 'John' then concat_ws('/', val, country, sex) end) as John,
max(case when name = 'Carla' then concat_ws('/', val, country, sex) end) as Carla,
. . .
from t
group by date;
如果您不事先知道所有名称，则存在动态枢纽问题，需要使用动态SQL（prepare / exec）。