我正在尝试在gridview上方显示一个搜索栏(来自流构建器)。希望搜索栏与gridview一起向上滚动。我尝试了多种方法将它们包装在扩展的/灵活的小部件中,但是我总是会遇到错误。有人管理过吗?
这就是我现在所拥有的,它将滚动,但搜索栏位于顶部。
new Column(
children: <Widget>[
new Flexible(
child: new Column(
children: <Widget>[
new Container(
margin: new EdgeInsets.only(left: 4.0, right: 4.0),
color: Colors.white,
child: new Row(
children: <Widget>[
new Container(
margin: new EdgeInsets.only(left: 8.0, right: 8.0, top: 8.0, bottom: 8.0),
child: Icon(Icons.search),
),
new Container(
child: Flexible(
child: new TextField(
onChanged: (String text) {
setState(() {
_searchController.text = text;
});
},
decoration: new InputDecoration.collapsed(hintText: 'Search...'),
controller: _searchController,
),
)
),
],
),
),
new Flexible(
child: new StreamBuilder(
stream: stgDocument.collection('people').orderBy('scroll').snapshots(),
builder: (context, snapshot) {
if (!snapshot.hasData) return const Text('Loading...');
_getMembers(snapshot);
return new GridView.builder(
//itemCount: snapshot.data.documents.length,
itemCount: _searchedMemberList.length,
gridDelegate: new SliverGridDelegateWithFixedCrossAxisCount(crossAxisCount: 2),
itemBuilder: (context, index) =>
_buildPeopleCards(context, _searchedMemberList[index]),
//_buildPeopleCards(context, snapshot.data.documents[index])
);
}
)
),
],
),
),
],
)
答案 0 :(得分:1)
您可以创建一个具有多个子级的可滚动ListView,一个子级为GridView,其子结构如下。要启用ListView
中所有元素的滚动,您需要将其参数physics
设置为NeverScrollablePhysics。
- ListView
- Container // your searchbar would go here
- GridView // physics: NeverScrollablePhysics
- Children
这是完整的代码示例:
import 'package:flutter/material.dart';
import 'package:cached_network_image/cached_network_image.dart';
void main() => runApp(MyApp());
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
theme: ThemeData(),
home: Scaffold(
body: ListView(
children: <Widget>[
Container(
color: Colors.red,
height: 50.0,
),
GridView.count(
physics: NeverScrollableScrollPhysics(),
crossAxisCount: 3,
shrinkWrap: true,
children: generateNumbers().map((int i) {
return Text(i.toString());
}).toList(),
)
],
),
),
);
}
List<int> generateNumbers() => List<int>.generate(30, (i) => i + 1);
}
这是结果: