Question

基于值contact为空的事实，我试图将一个JavaScript对象分成两个单独的数组。我在将值存储到单独的对象中时遇到麻烦，而且我不确定如何将它们存储在相应的对象中。我制作了一个fiddle来帮助您使用此代码。

var data = [{
    address: "234 BLUE WAY",
    addressType: "Mailing",
    city: "DONKY KONG CITY",
    contact: null,
    country: "US",
    email: "JANEER@GMAIL.COM",
    zipCode: "44222"
  },
  {
    address: "123 GETYO WAY",
    addressType: "Mailing",
    city: "NARNIA",
    contact: "JAMES DO",
    country: "US",
    email: "JAMES@MYEMAIL.COM",
    zipCode: "13123"
  }

];

var empContactInfoAddress;
var emergencyContactInfoAddress;

for (let d in data) {
  if (data[d].contact == null) {

    Object.keys(data[d]).forEach((key) => {
      this.empContactInfoAddress[d][key] = data[d][key];
    });
  } else {
    Object.keys(data[d]).forEach((key) => {
      this.emergencyContactInfoAddress[d][key] = data[d][key];
    });

  }
}
console.log('empContactInfoAddress', this.empContactInfoAddress)
console.log('emergencyContactInfoAddress', this.emergencyContactInfoAddress)

Answer 1

您可以基于filter()属性contact。

如果列表非常大，可以使用reduce之类的东西，这样一来就可以遍历数据。但是filter()很容易阅读，对我来说，除非有瓶颈，否则可以平衡额外的工作。

var data = [{address: "234 BLUE WAY",addressType: "Mailing",city: "DONKY KONG CITY",contact: null,country: "US",email: "JANEER@GMAIL.COM",zipCode: "44222"},{address: "123 GETYO WAY",addressType: "Mailing",city: "NARNIA",contact: "JAMES DO",country: "US",email: "JAMES@MYEMAIL.COM",zipCode: "13123"}];

let NoContact = data.filter(d =>  d.contact == undefined)
let Contact = data.filter(d => d.contact)

console.log("no contact: ", NoContact)
console.log("contact: ", Contact)

Answer 2

var data = [{
    address: "234 BLUE WAY",
    addressType: "Mailing",
    city: "DONKY KONG CITY",
    contact: null,
    country: "US",
    email: "JANEER@GMAIL.COM",
    zipCode: "44222"
  },
  {
    address: "123 GETYO WAY",
    addressType: "Mailing",
    city: "NARNIA",
    contact: "JAMES DO",
    country: "US",
    email: "JAMES@MYEMAIL.COM",
    zipCode: "13123"
  }

];

data.forEach(function(arrayItem, i) {
  var x = arrayItem;
  console.log(x);
});

Answer 3

要获得预期的结果，请使用以下使用if条件的条件选项，如果contact为null则推送到变量

var data = [
    {
        address: "234 BLUE WAY",
        addressType: "Mailing",
        city: "DONKY KONG CITY",
        contact: null,
        country: "US",
        email: "JANEER@GMAIL.COM",
        zipCode: "44222"
    },
    {
        address: "123 GETYO WAY",
        addressType: "Mailing",
        city: "NARNIA",
        contact: "JAMES DO",
        country: "US",
        email: "JAMES@MYEMAIL.COM",
        zipCode: "13123"
    }

];

var empContactInfoAddress =[];
var emergencyContactInfoAddress = [];

for (let d in data) {
   if(data[d].contact === null){
      empContactInfoAddress.push(data[d])
   }else{
     emergencyContactInfoAddress.push(data[d])
   }
}
console.log('empContactInfoAddress', empContactInfoAddress)
console.log('emergencyContactInfoAddress', emergencyContactInfoAddress)

Answer 4

您可以编写分区函数

function partition(array, predicate) {
  const positives = array.filter(predicate);
  const negatives = array.filter(value => !predicate(value));
  return [positives, negatives];
}

const [
  empContactInfoAddress,
  emergencyContactInfoAddress
] = partition(data, d => !d.contact);

为JavaScript对象指定两个单独的变量

4 个答案: