我试图等待我来自不同类的所有函数完成将数据追加到数组之前,然后继续。
我为dispath组创建了一个单例类。相反,当来自不同类的所有组都离开时,它会通知result(),它会单独执行。
class parralelRunner {
let dispatchGroup = DispatchGroup()
result(){
dispatchGroup.notify(queue: .main) {
print("All functions complete ")
}
}
}
class run1 {
func start(){
callAPI(){
filterresult()
}
}
callAPI(completion: (JSON)){
Alamofire.request("url", headers: headers).responseJSON { response in
if response.result.isSuccess{
completion(JSON(response.result.value!))
}else{
print("Binance - Couldn't import Request: Please check your internet connection")
}
}
}
func filterresult(){
parralelRunner.dispatchGroup.enter()
for .... {
}
parralelRunner.dispatchGroup.leave()
parralelRunner.result()
}
}
class run2 {
func start(){
callAPI(){
filterresult()
}
}
callAPI(completion: (JSON)){
Alamofire.request("url", headers: headers).responseJSON { response in
if response.result.isSuccess{
completion(JSON(response.result.value!))
}else{
print("Binance - Couldn't import Request: Please check your internet connection")
}
}
}
func filterresult(){
parralelRunner.dispatchGroup.enter()
for .... {
}
parralelRunner.dispatchGroup.leave()
parralelRunner.result()
}
}
答案 0 :(得分:1)
对parralelRunner.result()
的调用只能被调用一次。并且在每个异步过程的开始都需要对enter
进行调用,并在完成后相应地对leave
进行调用。
您需要做的第一件事是将run1
和run2
重构为类似这样的内容:
class run1 {
func start(){
parralelRunner.dispatchGroup.enter()
callAPI(){ JSON in
if let JSON = JSON {
filterresult()
}
parralelRunner.dispatchGroup.leave()
}
}
callAPI(completion: (JSON?)){
Alamofire.request("url", headers: headers).responseJSON { response in
if response.result.isSuccess{
completion(JSON(response.result.value!))
}else{
print("Binance - Couldn't import Request: Please check your internet connection")
completion(nil)
}
}
}
func filterresult() {
for .... {
}
}
}
然后无论使用run1
和run2
,您都需要类似以下内容:
run1.start()
run2.start()
parralelRunner.result()