我想从用户数据库中选择所有用户。代码可以工作,但是我想我错过了一些有关语法以及如何回显它的信息……因此它实际上检索到了他们,但是为每个数据生成了不同的表。 ...
我附上了图片
<?php
// seclect users from table
$selectUsers = "SELECT * FROM users ORDER BY userId DESC";
$selectUserKwery = mysqli_query($link, $selectUsers);
$userCount = mysqli_num_rows($selectUserKwery);
if($userCount > 0){
while ($userRow = mysqli_fetch_array($selectUserKwery)) { ?>
<div class="table-responsive">
<table class="table table-bordered" id="dataTable" width="100%" cellspacing="0">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
<th>Email</th>
<th>Join Date</th>
<th>ACTION</th>
</tr>
</thead>
<tfoot>
<tr>
<th>ID</th>
<th>Name</th>
<th>Email</th>
<th>Join Date</th>
<th>ACTION</th>
</tr>
</tfoot>
<tbody>
<tr>
<td><?php echo ucwords($userRow['userId']); ?></td>
<td><?php echo ucwords($userRow['userName']); ?></td>
<td>Edinburgh</td>
<td>61</td>
<td><p><a><i class="fa fa-fw fa-eye"></i></a> | <a><i class="fa fa-fw fa-edit"></i></a> | <a><i class="fa fa-fw fa-user-times"></i> </a> </p></td>
</tr>
</tbody>
</table>
<?php
}
} else if($userCount > 0) {
echo '<div class"alert alert-danger alert-dismissable">There are no Users yet</div>';
} ?>
所以我希望数据库结果显示在一个表中
新结果
答案 0 :(得分:0)
由于<table>
在while
中,因此您将获得多个表。您应该将表的结构元素移到while
之外,而只需在while
中创建行。像
?>
<div class="table-responsive">
<table class="table table-bordered" id="dataTable" width="100%" cellspacing="0">
<thead>
<tr>
<th>ID</th>
<th>Name</th>
<th>Email</th>
<th>Join Date</th>
<th>ACTION</th>
</tr>
</thead>
<tfoot>
<tr>
<th>ID</th>
<th>Name</th>
<th>Email</th>
<th>Join Date</th>
<th>ACTION</th>
</tr>
</tfoot>
<tbody>
<?php while ($userRow = mysqli_fetch_array($selectUserKwery)) { ?>
<tr>
<td><?php echo ucwords($userRow['userId']); ?></td>
<td><?php echo ucwords($userRow['userName']); ?></td>
<td>Edinburgh</td>
<td>61</td>
<td><p><a><i class="fa fa-fw fa-eye"></i></a> | <a><i class="fa fa-fw fa-edit"></i></a> | <a><i class="fa fa-fw fa-user-times"></i> </a> </p></td>
</tr>
<?php }/* close while */ ?>
</tbody>
</table>
应该这样做。您还可能应该在构建<table>
之前检查是否有结果。