Question

我已经创建了一条选择语句

SELECT [source_name]+''''/''''+[schema_name]+''''/''''+[table_name] AS [path], 
       [application_name], 
       [database_name], 
       [schema_name], 
       [table_name], 
       [source_name], 
       Substring(source_table_name, 0, 3)           AS source, 
       replace([query],''''desc'''',''''"DESC"'''') AS query, 
FROM   [cdi].[parameter_master] p (nolock) 
JOIN   [cdi].application_master a (nolock) 
ON     a.application_id = p.application_id

在这一部分 replace([query],''''desc'''',''''\"DESC\"'''') as query

[query]值为

SELECT a.desc, 
       a.occ_desc            AS occ_desc, 
       a.dth_dt              AS dth_dt, 
       a.hire_dt             AS hire_dt, 
       a.insd_empe_nbr       AS insd_empe_nbr, 
       a.surg_ind            AS surg_ind, 
       a.src_clm_pty_id      AS src_clm_pty_id, 
       a.elmtry_clm_anchr_id AS elmtry_clm_anchr_id, 
       a.lic_nbr_txt         AS lic_nbr_txt, 
       a.atty_hire_rsn_desc  AS atty_hire_rsn_desc, 
       a.atty_catg_desc      AS atty_catg_desc, 
       a.dfns_appt_dt        AS dfns_appt_dt, 
       a.empr_nm             AS empr_nm, 
       a.extl_refr_cd        AS extl_refr_cd, 
       a.src_sys_cd          AS src_sys_cd 
FROM   dbaall.pty_rol_in_clm a 
WHERE  a.e_tistmp >= timestamp('2018-01-01     00:00:00') 
OR     ( 
              a.e_to_tistmp >= timestamp('2018-01-01 00:00:00') 
       AND    a.e_to_tistmp < timestamp('2018-03-31 00:00:00'))

我只想将a.DESC替换为a.\"DESC\"

但是replace()函数会替换[query]字符串中所有出现的DESC。

我想写一个案例，当基于.desc的语句找到时，仅替换else字符串不应该被替换。

我该如何解决？

Answer 1

这段代码解决了这个问题： replace（[query]，''''a.DESC''''，''''a。\“ DESC \”''''）

在SQL Server中使用替换的情况

1 个答案: