Question

我有一个如下的sql查询

select profileName from user where (id) in ( select id FROM( SELECT user_id1 as id from user_connection where user_id2=(select id from user where profileName='deva') UNION ALL SELECT user_id2 as id from user_connection where user_id1=(select id from user where profileName='deva')) t GROUP BY id) ;

在终端上像魔术一样工作，但是在node.js上却有sql查询错误

exports.findFriends = function(userName,callback){
console.log('searching friends.... '+userName);
var findFriendsQuery = 'select profileName from user where (id) in ( select id FROM ( SELECT user_id1 as id from user_connection where user_id2=(select id from user where profileName= ? ) UNION ALL SELECT user_id2 as id from user_connection where user_id1=(select id from user where profileName=?)) t GROUP BY id)' ;
  db.query(findFriendsQuery,[userName],function(err,rows,fields){
    if(err){
     console.log(err);
     callback(1,-1,-1);
     }
    else{
        callback(0,rows,1);
        }
    });
};

sqlMessage：'您的SQL语法有错误；检查与您的MySQL服务器版本相对应的手册，以在第1行的\'？））t GROUP BY id）\'附近使用正确的语法， sqlState：“ 42000”，索引：0，

Answer 1

您已经两次使用了占位符（?），而一次仅通过了一次，您需要两次通过（[userName, userName]）

exports.findFriends = function(userName,callback){
console.log('searching friends.... '+userName);
var findFriendsQuery = 'select profileName from user where (id) in ( select id FROM ( SELECT user_id1 as id from user_connection where user_id2=(select id from user where profileName= ? ) UNION ALL SELECT user_id2 as id from user_connection where user_id1=(select id from user where profileName=?)) t GROUP BY id)' ;
  db.query(findFriendsQuery,[userName, userName],function(err,rows,fields){
    if(err){
     console.log(err);
     callback(1,-1,-1);
     }
    else{
        callback(0,rows,1);
        }
    });
};

sql查询不适用于node.js mysql，但适用于终端

1 个答案: