在尝试将个人记录插入数据库时,我遇到以下错误。
Caused by: java.sql.SQLSyntaxErrorException: ORA-02201: sequence not allowed here
我正在使用Hibernate 5.2.12.Final,Oracle 12 c数据库,并在数据库中使用Identity列作为'id'。
select 1 from dual
工作。因此,我确定数据库连接成功。
以下是配置:
数据库:
CREATE TABLE person
(
id NUMBER(18) GENERATED ALWAYS AS IDENTITY
INCREMENT BY 1 START WITH 1 NOT NULL,
name VARCHAR2(40) NOT NULL
);
ALTER TABLE person ADD CONSTRAINT pk_person PRIMARY KEY (id);
HibernateUtil
public class HibernateUtil {
private static StandardServiceRegistry registry;
private static SessionFactory sessionFactory;
public static SessionFactory getSessionFactory() {
if (sessionFactory == null) {
StandardServiceRegistry standardRegistry = new StandardServiceRegistryBuilder()
.configure(new File("path-to-hibernate.cfg.xml"))
.build();
Metadata metadata = new MetadataSources(standardRegistry)
.addAnnotatedClass(Person.class)
.addAnnotatedClassName("com.example.entity.Person")
.getMetadataBuilder()
.applyImplicitNamingStrategy(ImplicitNamingStrategyJpaCompliantImpl.INSTANCE)
.build();
sessionFactory = metadata.getSessionFactoryBuilder()
.build();
}
return sessionFactory;
}
public static void shutdown() {
if (registry != null) {
StandardServiceRegistryBuilder.destroy(registry);
}
}
}
人员实体:
@Entity
@Table(name = "Person")
public class Person implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
public Person(){}
public void setId(Long id) {
this.id = id;
}
public void setName(String name) {
this.name = name;
}
public Person(final String name){
this.name = name;
}
public Long getId() {
return id;
}
public String getName() {
return name;
}
@Column(name = "name")
private String name;
}
主要():
Session session = HibernateUtil.getSessionFactory().openSession();
session.beginTransaction();
session.save(new Person("code")); // Error here
session.getTransaction().commit();
session.close();
HibernateUtil.shutdown();
我们非常感谢您的帮助。:)
答案 0 :(得分:0)
相反,GenerationType.IDENTITY
尝试使用GenerationType.SEQUENCE
,它应该可以工作,请告诉我是否不是,因为除此之外,您的代码中没有其他问题。